A random sample of 341 residents of a city found that 62.2% approved of the mayor's job performance. Build a 81% CI for the proportion of city residents who approve of the mayor's job performance. a. First, confirm that there are at least 5 successes and 5 failures: There are successes and failures. b. Round your CI to three decimals.

Determine the question (X) that converts eachsituation to Yes/No data.a) The proportion of cars that are silver.b) Voter percentage who favor candidate Jones.c) The proportion of defective items

You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. How many randomly selected air passengers must you survey? Assume that you want to be 95% confident that the sample percentage is within 4.5 percentage points of the true population percentage. Complete parts (a) and (b) below. a. Assume that nothing is known about the percentage of passengers who prefer aisle seats. n= (Round up to the nearest integer.) b. Assume that a prior survey suggests that about 32% of air passengers prefer an aisle seat. n= (Round up to the nearest integer.)

Please see picture. Need this asap please and thank you.

Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…

Q7

K The accompanying data represent the wait time (in minutes) for a random sample of 40 visitors to a popular attraction in a large amusement park. Use the sample data to complete parts (a) through (d). Click the icon to view the data for wait times. Wait times 7 6454256200 15 32 23 8 . 9 44 10 9 33 55 1 27 6 9 6 Print 22 7 23 10 25 25 16 54 3 9 32 Done *** 0 3 6 12 5 3 7 8 13 7 16 C - X