A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 17 18 16 20 20 12 19 19 15 27 14 23 15 25 18 20 Click here for the Excel Data File Find a 90 percent confidence interval for µ, assuming that the sample is from a normal population. (Round your standa answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.) The 90% confidence interval to

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assist with the 90% confidence interval question 

A random sample of 16 pharmacy customers showed the waiting times below (in minutes).
17
15
18
27
16
14
20
20
15
12
25
19
18
19
20
23
Click here for the Excel Data File
Find a 90 percent confidence interval for u, assuming that the sample is from a normal population. (Round your standa
answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.)
The 90% confidence interval
to
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Transcribed Image Text:A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 17 15 18 27 16 14 20 20 15 12 25 19 18 19 20 23 Click here for the Excel Data File Find a 90 percent confidence interval for u, assuming that the sample is from a normal population. (Round your standa answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.) The 90% confidence interval to < Prev 7 of 10 Next >
Expert Solution
Step 1

we wants to find the 90% confidence interval .

as population parameters are unknown we use t test statistics to build 90 % confidence interval .

let us fist calculate sample mean and sample standard deviation .

waiting time (x )  Deviation (X - M) Squared Dev.
17 -1.62 2.64
18 -0.62 0.39
16 -2.62 6.89
20 1.38 1.89
20 1.38 1.89
12 -6.62 43.89
19 0.38 0.14
19 0.38 0.14
15 -3.62 13.14
27 8.38 70.14
14 -4.62 21.39
23 4.38 19.14
15 -3.62 13.14
25 6.38 40.64
18 -0.62 0.39
20 1.38 1.89
298    
M: 18.62   SS: 237.75

hence based on above table sample mean = 18.62

and standard deviation=  237.7515=3.9772

 

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