A random sample of 15 chemists from Washington state shows an average salary of $45720 with a standard deviation of $654. A random sample of 24 chemists from Florida state shows an average salary of $42403 with a standard deviation of $665. A chemist that has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At a=0.01 is this chemist correct? Let Washington be sample 1 and Florida be sample 2. The correct hypotheses are: O Ho: H1 < H2 HA: 41 > µ2(claim) O Ho: µ1 2 H2 HA: H1 < µ2(claim) O Ho: µ1 = µ2 HA: H1 + µ2(claim) Since the level of significance is 0.01 the critical value is 2.749 and -2.749 The test statistic is: |(round to 3 places) The p-value is: (round to 3 places) The decision can be made to: O reject Ho O do not reject Ho

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Question Three. 

**Hypothesis Testing for Chemist Salaries in Washington and Florida**

A random sample of 15 chemists from Washington state shows an average salary of $45,720 with a standard deviation of $654. A random sample of 24 chemists from Florida state shows an average salary of $42,403 with a standard deviation of $665. A chemist who has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At α = 0.01, is this chemist correct? Let Washington be sample 1 and Florida be sample 2.

**The correct hypotheses are:**

- \( H_0: \mu_1 = \mu_2 \)
- \( H_A: \mu_1 \neq \mu_2 \) (claim)

Since the level of significance is 0.01, the critical values are 2.749 and -2.749.

- **The test statistic is:** [blank] (round to 3 places)
- **The p-value is:** [blank] (round to 3 places)

The decision can be made to:

- \( \circ \) reject \( H_0 \)
- \( \circ \) do not reject \( H_0 \)

**The final conclusion is that:**

- \( \circ \) There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida.
- \( \circ \) There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida.
- \( \circ \) There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.
- \( \circ \) There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.
Transcribed Image Text:**Hypothesis Testing for Chemist Salaries in Washington and Florida** A random sample of 15 chemists from Washington state shows an average salary of $45,720 with a standard deviation of $654. A random sample of 24 chemists from Florida state shows an average salary of $42,403 with a standard deviation of $665. A chemist who has worked in both states believes that chemists in Washington make a different amount than chemists in Florida. At α = 0.01, is this chemist correct? Let Washington be sample 1 and Florida be sample 2. **The correct hypotheses are:** - \( H_0: \mu_1 = \mu_2 \) - \( H_A: \mu_1 \neq \mu_2 \) (claim) Since the level of significance is 0.01, the critical values are 2.749 and -2.749. - **The test statistic is:** [blank] (round to 3 places) - **The p-value is:** [blank] (round to 3 places) The decision can be made to: - \( \circ \) reject \( H_0 \) - \( \circ \) do not reject \( H_0 \) **The final conclusion is that:** - \( \circ \) There is enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is not enough evidence to reject the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida. - \( \circ \) There is not enough evidence to support the claim that chemists in Washington make a different amount than chemists in Florida.
Expert Solution
Step 1

To test
H0:μ1=μ2H1:μ1μ2

Step 2

The pooled standard deviation is
sp=n1-1s12+n2-1s22n1+n2-2=15-16542+24-1665215+24-2=5988024+1017117537=436735.108=660.8594

 

Then, the test statistic is
t=x1-x2sp1n1+1n2=45720-42403660.8594115+124=3317660.85940.3291=3317217.5154=15.249

 

The p-value is 0.

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