A random sample of 10 subjects have weights with a standard deviation of 13.0505 kg. What is the variance of their weights? Be sure to include units with the result. The variance of the sample data is (Round to four decimal places as needed.)

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was $425, $462, 5405, $234 a . Compute the range, sample variance, and sample standard deviation cost of repair. The range is $ s2 = dollars? (Round to the nearest whole number as needed.) s= SI (Round to two decimal places as needed.)

Find the ML estimator of the mean and variance from i.i.d. measurements from a normal distribution.

The sum of the squared deviation scores is SS = 247.6 for a population of N = 12 scores. What is the variance for this population? Be sure to submit a numeric response that is rounded to the nearest hundredth (2nd decimal place)

P3. Show that the mle of unknown standard deviation when the mean is known is different from the sample standard deviation when the random sample is taken from a normal population characterized by two parameters, mean and variance. Which estimator is unbiased? Justify your answer. Show that a sample mean is a minimum variance unbiased estimator of the mean of a normal population with known variance.

IF THE VARIANCE OF A POPULATION IS 0.75, THE STANDARD DEVIATION MUST BE?

Compute the (sample) variance and standard deviation of the data sample. (Round your answers to two decimal places.) −1, 7, 7, 3, 14 Variance: Standard Deviation:

If we meet these conditions, the sampling distribution of the mean will have a normal shape and ... The mean of the sampling distribution will be u, (i.e., the same as the population mean) and the standard deviation of the sampling distribution will be (that's the population standard deviation divided by the square root of the sample size). In the AP Stats Guy video, he talks about the number of text messages his students send during class. Suppose the average number of text messages his students send during class is u = 30 text messages. If we take samples of say, n = 36 students at a time, we would expect the mean of the sampling distribution we create to be the same as the population mean, 30 text messages. If we can further say that standard deviation of the number of text messages is 12 text messages, by how much would we expect the sample means to vary? (hint, use the formula above) text messages