A random sample of 10 children found that their average growth for the first year was 9.8 inches, with a standard deviation of 0.96 inches. Find the 85% confidence interval of the mean growth of all American children in the first year of life. What is the name of the confidence interval? One Proportion z Interval One Sample z Interval Two Proportion z Interval Chi-Square Goodness of Fit Interval Correlation t Interval Two Independent Samples t Interval Chi-Square Interval for Independence ANOVA One Sample t Interval Paired Samples t Interval

MATLAB: An Introduction with Applications
6th Edition
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Author:Amos Gilat
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A random sample of 10 children found that their average
growth for the first year was 9.8 inches, with a standard
deviation of 0.96 inches. Find the 85% confidence interval
of the mean growth of all American children in the first
year of life.
What is the name of the confidence interval?
One Proportion z Interval
One Sample z Interval
Two Proportion z Interval
Chi-Square Goodness of Fit Interval
Correlation t Interval
Two Independent Samples t Interval
Chi-Square Interval for Independence
ANOVA
One Sample t Interval
Paired Samples t Interval
Transcribed Image Text:A random sample of 10 children found that their average growth for the first year was 9.8 inches, with a standard deviation of 0.96 inches. Find the 85% confidence interval of the mean growth of all American children in the first year of life. What is the name of the confidence interval? One Proportion z Interval One Sample z Interval Two Proportion z Interval Chi-Square Goodness of Fit Interval Correlation t Interval Two Independent Samples t Interval Chi-Square Interval for Independence ANOVA One Sample t Interval Paired Samples t Interval
Have the assumptions been met? Check which assumptions
have been met.
Two outcomes
Normal Sampling Distribution: np 2 5 & n(1 - p) 2 5
Known population standard deviation
The proportion is constant
Normal Sampling Distribution: n,p, 2 5, n,(1 - P,) 2 5
np, 2 5 & n(1 - P,) 2 5
Independent trials
Fixed number of trials
Expected values 2 5
Unknown population standard deviation
Normal Sampling Distribution: n 2 30 or Population
is normally distributed
Independent samples
Random sample
Equal population variances
Transcribed Image Text:Have the assumptions been met? Check which assumptions have been met. Two outcomes Normal Sampling Distribution: np 2 5 & n(1 - p) 2 5 Known population standard deviation The proportion is constant Normal Sampling Distribution: n,p, 2 5, n,(1 - P,) 2 5 np, 2 5 & n(1 - P,) 2 5 Independent trials Fixed number of trials Expected values 2 5 Unknown population standard deviation Normal Sampling Distribution: n 2 30 or Population is normally distributed Independent samples Random sample Equal population variances
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