A pump with a volumetric displacement of 4 in^3/rev runs at 3600 rpm and produces 1500 psi. The actual flow rate is 59 gpm. What is the volumetric efficiency of this pump? Enter a whole number percentage

Show in Figure 1 is the water flow system. The velocity head difference is .  Volume flow rate is .  The heights are  and , respectively.  The power output from the motor is , . The energy added by the pump is . The energy loss between point 1 and 2 is . Calculate  4)  the pressure head difference  in meter_________ m

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Displacement (c): 0.2 in3/revShank diameter (d) = 0.625 in.Piston diameter (D) = 1.5 in.Rotation speed (n): 1725 RPMPressure (P): 600 PSIStroke (L) = 18in.   a) Calculate the theoretical flow rate of the pump in in3/min and US GPM.Theoretical flow (Q) = Theoretical displacement (C) x Speed of revolution (n)Theoretical flow (Q) = 0.2 in3/rev x 1725 rpmTheoretical flow (Q) = 345 in3/min = 1.49 US GPM b) Calculate the cylinder output speed in in/s.Cylinder output speed (VS) = Piston side flow (Q) / Piston area (Ap)Cylinder output speed (VS) = (Displacement x Speed of revolution) / Piston area (Ap)Cylinder output speed (VS) = (0.2 in3/rev x 1725 RPM) / 1.77 in2Cylinder output speed (VS) = (0.2 in3/rev x 1725 RPM) / 1.77 in2Cylinder output speed (VS) = 196.02in/s = 196.02 / 60s = 3.20 in/s Questions: c) Knowing the output velocity (ram speed), calculate the rod side flow in GPM when the ram is extending. d) Calculate the piston exit time in seconds. e) Calculate the piston entry time in…