A pump is being used to lift water from the bottom elbow, tank to the top tank in a pipe of diameter (d) at a discharge (Q). The pipe system comprises four 90" threaded elbows. The pipe entrance is sharp-edged, and the pipe exit is sudden. An Angle Valve (fully- open) is used to control the discharge in the pipeline. elbow PanpX Given the values of Q [L/s], and d [cm], calculate the power loss due to components (i.e., minor loss) in the pipe (Pminor loss) in [W]. elbow Valve elbow Givens: Q = 9.34 d = 9.296 Answers: (1) 97.587 (2) 52.043 (3) 83.932 (4) 61.849

please do step by step     The pipe in figure discharges water from an upper tank to a lower tank as shown. The pipe consists of 500-ft long of a 6-in diameter wrought iron (f = 0.016) Neglect minor losses.

Question 6 In the schematic below, water flows through the pipe and enters a sudden contraction nozzle. To hold the nozzle in place, calculate the axial component of an anchoring force (FA) that would be necessary. Provide a sketch of your control volume. p = 1.940 slugs/fts, 1 ft = 12 inches, 1 lb-s? = 1 slug-ft Section (1) Uniform flow P-75[psi] V,-25[ft/s] Section (2) Uniform flow P2=0 [psi] V=100[ft/s] D;=3 [in] Flow in circular pipe Flow in circular pipe Sudden contraction nozzle

Determine the discharge, HGL, and EGL. Water 20°C 4-cm-dia. wrought iron pipe 20 m 50 m 20 m Screwed elbows 40 m