A proton (q = 1.60 x 10-19 C, m= 1.67 x 10-2" kg) move in a uniform magnetic field B = 0.500 Tî . At t = 0 the proton has velocity components v = 1.50 x 10° m/s, vy = 0, and v: = 2.00 x 10° m/s. In addition to the magnetic field there is a uniform electric field in the negative x- direction, Ē = (-3.00×10ʻ V/m)î. (a) Describe the || path of the proton. Does the electric field affect the radius of the helix? Explain. (b) At t = T/2, where T is the period of the circular motion of the proton, what is the x-component of the displacement of the proton from its position at t= 0?

A proton (q = 1.60 x 10-19 C, m= 1.67 x 10-2" kg) move in a uniform magnetic field B = 0.500 Tî . At t = 0 the proton has velocity components v = 1.50 x 10° m/s, vy = 0, and v: = 2.00 x 10° m/s. In addition to the magnetic field there is a uniform electric field in the negative x- direction, Ē = (-3.00×10ʻ V/m)î. (a) Describe the || path of the proton. Does the electric field affect the radius of the helix? Explain. (b) At t = T/2, where T is the period of the circular motion of the proton, what is the x-component of the displacement of the proton from its position at t= 0?

Physics for Scientists and Engineers

10th Edition

ISBN:9781337553278

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Physics And Measurement

Section: Chapter Questions

Problem 26P: Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.

See similar textbooks

Similar questions

Which of the following equations repreşents a power relationship? Select one: C =8+0.016 a. O b. N=14e0.01t O c. y = 3x-1 d. V =10t+3 %3D С. %3D
A particle moves along a portion of the parabolic path y? = 4 – x, where x and y are in meter, within the time interval 0
iii)compute the value of n?
Review. Prove that one solution of the equation 2.00x43.00x3+5.00x=70.0 is x = 2.22.
27. Review. A 5.75-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.00 m/s and its y component of velocity is -3.00 m/s. (a) What is the kinetic energy of the object at this time? (b) At a later time t = 2.00 s, the particle is located at x = 8.50 m and y = 5.00 m. What constant force acted on the object during this time interval? (c) What is the speed of the particle at t = 2.00 s?
P2 = 50 Pa U, = ??? P1 = 200 Pa Ah =10 m υ, 10 m/s
-1 3. -2 х + 4, 9. Solve X' subject to 3 3 X(0)
The answer in number 15 should be 800 J. You must answer no. 15 and 18. THANK YOU IN ADVANCE. I HOPE YOU CAN ANSWERS THOSE HOSE QUESTIONS.
In the following figure, 1 represents Ts 1 2 3 а. Vmp O b. Vrms C. average v o d. (1/average v)1
7)Solve the sub-part (a) only.
(A) m 5.00 m 3.20 m 2.00 m Figure P8.3 3. A block of mass m - 5.00 kg is released from point @ and V slides on the frictionless track shown in Figure P8.3. Deter- mine (a) the block's speed at points ® and © and (b) the net work done by the gravitational force on the block as it moves from point @ to point ©.
56. If (6.00 i – 8.00 j)m, B = (-8.00 i +3.00 j )m, and A = (26.0 i + 19.0 j )m , find the unknown constants a D +b B + A = 0. and b such that a