A proton is traveling through a region of space containing both a magnetic and electric field. At one instant in time, the velocity is = ( 89000 i +60100 ĵ) m/s and the acceleration is à = ( 8.70 k) x 10⁹ m/s². If B = ( 1.51 k) mT, what is the magnitude of the electric field? i N/C

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.45 T. 1. What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 6.1 × 107 m/s? 2. Find the radius of curvature, in meters, of the path of a proton accelerated through this same potential after the proton crosses into the region with the magnetic field. 3. What is the ratio of the radii of curvature for a proton and an an electron traveling through this apparatus?

The Russian physicist P. A. C˘ erenkov discovered that a charged particle traveling in a solid with a speed exceeding the speed of light in that material radiates electromagnetic radiation. (This is analogous to the sonic boom produced by an aircraft moving faster than the speed of sound in air; see Section 16.9. C˘ erenkov shared the 1958 Nobel Prize for this discovery.) What is the minimum kinetic energy (in electron volts) that an electron must have while traveling inside a slab of crown glass (n = 1.52) in order to create this C˘ erenkov radiation?

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A proton enters a region of uniform magnetic feild (B) = (0.020 I)T and a uniform electric feild E . When the velocity of the proton is (3000k) m/s, it experiences an acceleration of (9.6x10^9 j) m/s². The magnitude E of the electric feild is equal to what? The options below have units V/m. a. 160 V/m b. 100 V/m c. 60 V/m d. 40 V/m e. 0

Pls find Fbx and Fby for c

The magnetic force dFg on a infinitesimal segment of current I is dFs = I dEx B Where di is the displacement vector of the infinitesimal current segment. The total magnetic force on a finite current segment is F = 1J (dL x B) 1. If the magnetic field is uniform in space the magnetic force on current simplifies to FB = {(x5). What is vector in this expression? Choose one. is the length of the current segment is the vector from the point where the current enters the uniform field to the point where the current leaves the uniform field. a. What is the magnetic force on the portions of the wire to the left of the dashed line? • is the current. 2. The magnetic field is zero to the left of the dashed line. The magnetic field to the right of the dashed line is uniform outwards. A current carrying wire goes through the region as shown. b. What is the magnetic force on the bottom wire segment? Write answer in component vector form. c. What is the magnetic force on the slanted wire segment?…

A particle with positive charge q moves with a velocity v = (51 + 2ĵ- k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. Let B = (3î + 5ĵ + Â) T and Ể = (E¸î + Eĵ + E₂Â) V/m. For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) Ex = 7 x V/m Ey = X V/m E₂ = V/m 10

. A uniform electric field E and a uniform magnetic field B are present in some region. A particle with positive charge q and mass m moves with speed v to the right. a. What do the directions of the electric field and magnetic field need to be in order for the particle to move with constant speed? Ignore gravity, air resistance and any other non-electromagnetic forces. b. Find the ratio E/B in order for the particle to move at constant speed.

An electron with initial velocity vo = 1.96 x 105 m/s enters a region 1.0 cm long where it is electrically accelerated (see the figure). It emerges with velocity v = 5.04 x 106 m/s. What is its acceleration, assumed constant? (Such a process occurs in conventional television sets.) Number i 2.3480E13 Units Nonaccelerating Accelerating region region Path of electron Source of high voltage m/s^2