A proton is released from rest in a region ofspace with a nonzero electric field. (a) As the proton moves, doesthe electric potential energy of the system increase, decrease, orstay the same? (b) Choose the best explanation:I. As the proton begins to move, its kinetic energy increases. Theincrease in kinetic energy is equal to the decrease in the electric potential energy of the system.II. Because the proton has a positive charge, its electric potentialenergy will always increase.III. The proton will move perpendicular to the electric field, andhence its electric potential energy will remain the same
A proton is released from rest in a region ofspace with a nonzero electric field. (a) As the proton moves, doesthe electric potential energy of the system increase, decrease, orstay the same? (b) Choose the best explanation:I. As the proton begins to move, its kinetic energy increases. Theincrease in kinetic energy is equal to the decrease in the electric potential energy of the system.II. Because the proton has a positive charge, its electric potentialenergy will always increase.III. The proton will move perpendicular to the electric field, andhence its electric potential energy will remain the same
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
A proton is released from rest in a region of
space with a nonzero electric field. (a) As the proton moves, does
the electric potential energy of the system increase, decrease, or
stay the same? (b) Choose the best explanation:
I. As the proton begins to move, its kinetic energy increases. The
increase in kinetic energy is equal to the decrease in the electric potential energy of the system.
II. Because the proton has a positive charge, its electric potential
energy will always increase.
III. The proton will move perpendicular to the electric field, and
hence its electric potential energy will remain the same
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