A proton is fired horizontally into a 1.0×105N/C vertical electric field. It rises 1.0 cm vertically after having traveled 6.0 cm horizontally. What was the proton's initial speed?

A constant electric field of 20.0 N/C points along the positive x-direction. An electron, initially at rest, moves a distance of 0.500 m in this space. How fast is the electron moving after its 0.500 m journey?

A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude of the electric field is 1.46  105 N/C.  What is the speed of the proton after it has traveled 7.00 cm?  What is the speed of the proton after it has traveled 70.0 cm?

An electron has an initial speed of 5.21 x 106 m/s in a uniform 4.69 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity O not enough information to decide (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? (d) What is the electron's speed when it returns to its starting point? m/s