A program of 33 bytes is loaded into memory. The Data Segment is shown below: .DATA DB 3Ah, 12, 10101101b X S DB 5 DUP(3Bh) Y DW 33ABh What is the offset address of Y? 0000 0009 0008 O 0007
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- In executing the following code: START: MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: MOV AL, (SI) XOR (DI), AL INC SI INC DI DEC CX JNZ LOOP HLT with the following byte contents: (0300H) = OAH, (0301H) = OBH, (0302H) = 11H, (0303H) = 21H. The result will be:In executing the following code: MOV CX, 0002 START: MOV SI, 0300 MOV DI, 0302 LOOP: XOR (DI), AL INC SI MOV AL, (SI) INC DI DEC CX JNZ LOOP HLT with the following byte contents: (0300H) = 0AH, (0301H) = OBH, (0302H) = 11H, (0303H) = 21H. The result will be: Select one: a. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1AH, (0303H) = 2BH (0300H) = 0AH, (0301H) = OBH, (0302H) = 10H, (0303H) = 20H b. c. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1AH, (0303H) = 20H d. None of the options given here e. (0300H) = 0AH, (0301H) = OBH, (0302H) = 1BH, (0303H) = 2AHFive Byte values (1, 2, 3, 4, 5) are created in a BitArray by a c# application, which also shows each byte in its correct binary form:
- In execution of the following code with the following bytes contents: START: CLC MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: MOV AL, (DI) ADC (SI), AL INC SI INC DI DEC CX JNZ LOOP HLT (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH. %3D %3D %3D The result will be:The following c# application builds a BitArray of five Byte values (1,2,3,4,5) and shows each byte in its correct binary form:In execution of the following code with the following bytes contents: START: CLC MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: ADC (SI), AL INC SI INC DI DEC CX JNZ LOOP HLT 3CH, (0303H) = 4DH. MOV AL, (DI) (0300H) = 1AH, (0301H) = 2BH, (0302H) = The result will be: a. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 66H, (0303H) = 77H b. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH C. (0300H) = 1AH, (0301H) = 2BH, (0302H) = 56H, (0303H) = 87H d. None of the options given here. Select one:
- Menus The local diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert. There are four appetizers, five soups, three main courses, and four desserts. Your diet restricts you to choosing between a dessert and an appetizer. (You cannot have both.) Given this restriction, how many three-course meals are possible? A computer byte consists of eight bits, each bit being either a 0 or a 1. Assume that characters are represented using a code that uses a byte for each character. Some written languages, such as Chinese and Japanese, use tens of thousands of different characters. If a language uses roughly 97,000 characters, a computer code for this language would have to use how many bytes per character?Please write the code in MIPS assembly Language Create a MIPS program that corrects bad data using Hamming codes. ECC Hamming codes are explained on pages 420-424 in your text. The program is to request the user to enter a 12-bit Hamming code and determine if it is correct or not. If correct, it is to display a message to that effect. If incorrect, it is to display a message saying it was incorrect and what the correct data is (the 12-bit Hamming code) again in hex. I will be testing only with single bit errors, so the program should be able to correct my tests just fine. You do not need to worry about multiple bit errors. Make certain that you have lots of comments in your code as this is in MIPS. Also make the code neat: line up the command field, the register fields, and the comment fields For this assignment, turn in your code, a screenshot showing a working test caseWrite assembly language program Write a program that adds 5 bytes of data and save the result, the data should be following hex numbers 25H, 12H, 15H, 1FH, and 2BH [only by using LOOP]
- Write 3 different program segments to store (05)H in memory location (2850)H8. Implement the following equations using a single 8x 3 ROM а. АВС + АВС b. АВС + AВС + АВС с. АВС + AВС + АВС + АВСCreate a 4-bit by 3-bit binary multiplier that multiplies a 4-bit number by a 3-bit number. Note: The 4-bit number should be the multiplicand and the 3-bit number should be the multiplier.