A production process is checked periodically by a quality control inspector. The inspector selects simple random samples of 30 finished products and computes the sample mean product weight T. If test results over a long period of time show that 5% of the T values are over 2.1 pounds and 5% are under 1.9 pounds, what are the mean and the standard deviation for the population of products produced with this process? Use z-table. Mean (to 1 decimal) Standard deviation (to 2 decimals)

A normal distribution has a mean of 140 and a standard deviation of 7. Find the z-score for a data value of 141.

Weights of one-year-old male German Shepherd dogs have a standard deviation of 1.5 lbs. Determine the percentage of all samples of 200 one-year-old male German Shepherds that have mean weights within 0.125 lb of the population mean weight of all one-year-old German Shepherds.

Assume the random variable X is normally distributed, with mean u= 44 and standard deviationo = 9. Find the 13th percentile.

The empirical rule estabilishes the percentages that are 1,2, and 3 deviations from the mean True Flase

Assume that IQ scores follow a Normal distribution with µ=100 and σ=16.  Using our IQR rule for determining IQ score outliers, what IQ scores would establish the lower and upper fences for determining outliers?

With a mean of 10 and standard deviation of 5. Assume that the population data are normally distributed.  Calculate the z-score for a raw score of 5. What proportion of the distribution is equal to or less than this score?

Length of skateboards in a skateshop are normally distributed with a mean of 32 in and a standard deviation of 0.6 in. The figure below shows the distribution of the length of skateboards in a skateshop. Calculate the shaded area under the curve.

Assuming a population mean of 900 and a population standard deviation of 200 for LCSW scores. What percentage of individuals have LCSW scores greater than 1100? Plot answer on a normal distribution curve.

Scores on the GRE (Graduate Record Examination) are normally distributed with a mean of 506 and a standard deviation of 81. Use the 68-95-99.7 Rule to find the percentage of people taking the test who score between 425 and 506. The percentage of people taking the test who score between 425 and 506 is 68 %.