A potter's wheel—a thick stone disk with a radius of 0.570m and a mass of 118kg—is freely rotating at 41.0rev/min. The potter can stop the wheel in 5.30s by pressing a wet rag against the rim and exerting a radially inward force of 68.1N. Calculate the effective coefficient of kinetic friction between the wheel and the rag.

John is pushing his daughter Rachel in a wheelbarrow when it is stopped by a brick 8.00 cm high (see the figure below). The handles make an angle of 0 = 20.0° with the ground. Due to the weight of Rachel and the wheelbarrow, a downward force of 407 N is exerted at the center of the wheel, which has a radius of 18.0 cm. Assume the brick remains fixed and does not slide along the ground. Also assume the force applied by John is directed exactly toward the center of the wheel. (Choose the positive x-axis to be pointing to the right.) & (a) What force (in N) must John apply along the handles to just start the wheel over the brick? 1690.53 X Your response differs from the correct answer by more than 10%. Double check your calculations. N (b) What is the force (magnitude in kN and direction in degrees clockwise from the -x-axis) that the brick exerts on the wheel just as the wheel begins to lift over the brick? magnitude KN direction ° clockwise from the -x-axis

A coin rests 15.8 cm from the center of a turntable. The coefficient of static friction between the coin and turntable surface is 0.350. The turntable starts from rest at t = 0 and rotates with a constant angular acceleration of 0.622 rad/s2. (a) Once the turntable starts to rotate, what force causes the centripetal acceleration when the coin is stationary relative to the turntable? Under what condition does the coin begin to move relative to the turntable? the static friction causes the cenripetal acceleration (b) After what period of time will the coin start to slip on the turntable? 6.55

A flywheel in the form of a uniformly thick disk of radius 1.68 m1.68 m has a mass of 54.1 kg54.1 kg and spins counterclockwise at 209 rpm209 rpm. Calculate the constant torque required to stop it in 1.00 min1.00 min.

What is the linear speed due to the Earth’s rotation of a point on the Earth (latitude 36.0 N)? The mean radius of the Earth is RE = 6.38 × 106 m, T = 24 hours.

The motor of a table saw is rotating at 3450 rev/min. A pulley attached to the motor shaft drives a second pulley of half the diameter by means of a V-belt. A circular saw blade of diameter 0.208 m is mounted on the same rotating shaft as the second pulley. (a) The operator is careless and the blade catches and throws back a small piece of wood. This piece of wood moves with linear speed equal to the tangential speed of the rim of the blade. What is this speed? (b) Calculate the radial acceleration of points on the outer edge of the blade to see why sawdust doesn’t stick to its teeth.

If the forearm rotates about the elbow an angular distance of 13.179 degrees, what is the linear distance traveled by the wrist? Assume the forearm is 0.13 m in length

A coin rests 14.5 cm from the center of a turntable. The coefficient of static friction between the coin and turntable surface is 0.310. The turntable starts from rest at t = 0 and rotates with a constant angular acceleration of 0.640 rad/s2. (a) Once the turntable starts to rotate, what force causes the centripetal acceleration when the coin is stationary relative to the turntable? Under what condition does the coin begin to move relative to the turntable? (b) After what period of time will the coin start to slip on the turntable? s

The angular displacement of the centrifuge is given by 0 = 3.6[t+ 20e-0.019t-20] rad, where t is in seconds and t = 0 is the startup time. If the person loses consciousness at an acceleration level of 9.1g, determine the time t at which this would occur. Verify that the tangential acceleration is negligible as the normal acceleration approaches 9.1g. Answer: t = Mi 33.6' 8 sec

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