A positively charged particle of mass 6.82 x 10-8 kg is traveling due east with a speed of 64.2 m/s and enters a 0.397-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 4.06 x 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge

In the figure below, the current in the long, straight wire is Iy=16 A, and the wire lies in the plane of the rectangular loop, which carries a current of I=10.0 A. The dimensions in the figure are c= 0.100 m, a=0.150 m, and, l= 0.450 m. Find the magnitude of the net force ( in units of uN) exerted on the loop by the magnetic field created by the wire. Select one: OA. 86.4 OB. 54.4 OC. 48.0 OD. 94.4 OE 118.4 Activate Windows GotoSettinos to ateWindows ENG 9:52 PM UK 5/24/2021

One component of a magnetic field has a magnitude of 0.0383 T and points along the +x axis, while the other component has a magnitude of 0.0735 T and points along the -y axis. A particle carrying a charge of +2.22 × 10-5 C is moving along the +z axis at a speed of 4.97 x 10³ m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis. (a) Number (b) Number i IN Units Units By +q

One component of a magnetic field has a magnitude of 0.0450 T and points along the +x axis, while the other component has a magnitude of 0.0702 T and points along the -y axis. A particle carrying a charge of +2.23 × 10-5 C is moving along the +z axis at a speed of 4.63 x 10³ m/s. (a) Find the magnitude of the net magnetic force that acts on the particle. (b) Determine the angle that the net force makes with respect to the +x axis. By B V +q

A point charge of q 2.0 µC moves with a velocity of v (3.0 i +4.0 j) x10° m/s in a uniform magnetic field of B-0.4 k T. Find the magnitude of the magnetic force (in N) on the charge.

A uniform magnetic field B = 1.7 x 10-4 T exists in +x direction. A proton (q = +e,  and mp = 1.67 x 10-27 kg) is shot through the field in the +y direction with a speed of 3.5 x 105 m/s. Find the magnitude and direction of the magnetic force FB on the proton.

A proton moves perpendicularly to a uniform magnetic  at 1.0 * 107 m/s and experiences an acceleration of 2.0 * 1013 m/s2  in the +x when it velocity is in the +z direction. Determine the magnitude and direction of the field

A charged particle moves with a speed of 6.0×103 m/s perpendicularly into an uniform magnetic field of magnitude 0.20 T.  The charge of the particle is 5.8 ×10-16 C, mass of the particle is 1.2 ×10-21kg. (a) What is the magnitude of the magnetic force on the particle?  (b) What could be the radius of the path of the particle if it moves inside the B-field?(c) To avoid the particle being deflected by the magnetic field, (so particle can move straight through the B-field,) an electric field is applied at the same location. What is the magnitude of the E-field? HTML EditorKeyboard Shortcuts

A particle with charge q enters a region with a uniform magnetic field Bthat acts in x and z directions (By = 0). The initial velocity of the particle is v = 2î +3ŷ. The force acting on the particle is given by F = q(-3 î + 2ĵ – 9k). Find the magnetic field vector B O a. B= -3î – k O b. B = 3î . O c. B= 2î + 3k O d. B= 4î – 2k O e. B= 2î – 3k