A population of values has a normal distribution with u to draw a random sample of size n = 179. = : 245.3 and ♂ = 80.6. You intend Find the probability that a single randomly selected value is between 227.2 and 241.1. P(227.2 < X < 241.1) = 0.2514 x Find the probability that a sample of size n = 179 is randomly selected with a mean between 227.2 and 241.1. P(227.2 < M 241.1) = 0.0016 X < Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z- scores or z-scores rounded to 3 decimal places are accepted.

An IQ test is designed so that the mean is 100 and the standard deviation is 10 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 99​% confidence that the sample mean is within 8 IQ points of the true mean. Assume that σ=10 and determine the required sample size.

A random sample of a population of size n = 36, find the prob that the mean is between 110 and 115. The pop u is 100, and the sd is 15.

Use the formula to find the standard error of the distribution of differences in sample means, x⎯⎯1−x⎯⎯2x¯1-x¯2.Samples of size 100 from Population 1 with mean 95 and standard deviation 10 and samples of size 80 from Population 2 with mean 76 and standard deviation 17Round your answer for the standard error to two decimal places.standard error =

Use the formula to find the standard error of the distribution of differences in sample means, x⎯⎯1−x⎯⎯2x¯1-x¯2.Samples of size 40 from Population 1 with mean 3.7 and standard deviation 1.9 and samples of size 40 from Population 2 with mean 1.9 and standard deviation 1.2Round your answer for the standard error to two decimal places.standard error = Enter your answer in accordance to the question statement

n=16  mean number of  television per household is 4 with a standard deviation of 1 television. using chebychev's theorem, detemine at least how many households have between 2 and 6 television.

Dandelions have effects on crop production and lawn growth and are studied. In one region, the mean number of dandelions per square meter was found to be 10.8.Find the probability of no dandelions in an area of 1 m².P(X=0)=P(X=0)= Find the probability of at least one dandelion in an area of 1 m².P(at least one) = Find the probability of at most two dandelions in an area of 1 m².P(X≤2)=P(X≤2)=

Chebyshev's Theorem states that for any distribution of numerical data, at least 1-1/k? of the numbers lie within The percent of numbers between 88 and 112 is at least %. k standard deviations of the mean. (Round to the nearest hundredth as needed.) In a certain distribution of numbers, the mean is 100, with a standard deviation of 6. Use Chebyshev's Theorem to tell what percent of the numbers are between 88 and 112.

A population of values has a mean of 59.6 and standard deviation of 35.4. Find the probability that a sample of 58 values from this population will have a mean between 52.6 and 63.8.Enter your answers as numbers accurate to 4 decimal places.