MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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A popular social media platform has begun offering
stock shares to the public. In the past 2 years, the
price of the stock has generally increased. An
investment specialist gathers data on the stock price
over the past 2 years and proppses two models for
estimating the growth of the steck, as shown in the
scatterplots.
Based on the scatterplots, which type of model is
most suitable for estimating the stock price?
O A power model is suitable because the scatterplot
of log(weeks) against log(stock price) shows a
curved relationship.
O A linear model is suitable because the scatterplot
of weeks against log(stock price) shows a strong
linear relationship.
log(Stock Price) vs. Weeks
O An exponential model is suitable because the
scatterplot of log(weeks) against log(stock price)
shows a curved relationship.
2.28
2.26
2.24
222
2.2
2.18
2.16
2.14
212
O An exponential model is suitable because the
scatterplot of weeks against log(stock price) shows
a strong linear relationship.
2.1
2.08
206
log(Stock Price)
expand button
Transcribed Image Text:A popular social media platform has begun offering stock shares to the public. In the past 2 years, the price of the stock has generally increased. An investment specialist gathers data on the stock price over the past 2 years and proppses two models for estimating the growth of the steck, as shown in the scatterplots. Based on the scatterplots, which type of model is most suitable for estimating the stock price? O A power model is suitable because the scatterplot of log(weeks) against log(stock price) shows a curved relationship. O A linear model is suitable because the scatterplot of weeks against log(stock price) shows a strong linear relationship. log(Stock Price) vs. Weeks O An exponential model is suitable because the scatterplot of log(weeks) against log(stock price) shows a curved relationship. 2.28 2.26 2.24 222 2.2 2.18 2.16 2.14 212 O An exponential model is suitable because the scatterplot of weeks against log(stock price) shows a strong linear relationship. 2.1 2.08 206 log(Stock Price)
log(Stock Price) vs. log(Weeks)
2.28
2.26
2.24
2.22
22
2.18
2.16
2.14
2.12
21
2.08
2.06
2.04
0.5
1.
1.5
12,
log(Weeks)
log(Stock Price)
expand button
Transcribed Image Text:log(Stock Price) vs. log(Weeks) 2.28 2.26 2.24 2.22 22 2.18 2.16 2.14 2.12 21 2.08 2.06 2.04 0.5 1. 1.5 12, log(Weeks) log(Stock Price)
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