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A poll conducted in 1972 asked 1009 people, "During the past year, about how many books, either hardcover or paperback, did you read either all or part of the way through?" Results of the survey indicated that x= 18.9 books and s= 19.9 books. (a) Construct a 99% confidence interval for the mean number of books read either all or part of during the preceding year. Interpret the interval. (b) Compare these results to a recent survey of 1009 people. The results of the survey indicated that x= 13.1 books and s= 16.2 books. A 99% confidence interval for this survey is (11.78, 14.42). Were people reading more in 1972 than they are today? а г Click the icon to view the table of areas under the t-distribution. (a) The 99% confidence interval for 1972 is (.). (Use ascending order. Round to two decimal places as needed.) Interpret the confidence interval. Which of the following is correct? (b) Were people reading more in 1972 than they are today? O A. Yes, people were reading more in 1972 than they are reading today, because the confidence intervals do not cross and have no common outcomes. O B. No, people were reading less in 1972 than they are reading today because the confidence intervals do not cross and have no common outcomes. O C. People were reading approximately the same number of books in 1972 as they are today because the intervals cross and have some common outcomes.

A poll conducted in 1972 asked 1009 people, "During the past year, about how many books, either hardcover or paperback, did you read either all or part of the way through?" Results of the survey indicated that x= 18.9 books and s= 19.9 books. (a) Construct a 99% confidence interval for the mean number of books read either all or part of during the preceding year. Interpret the interval. (b) Compare these results to a recent survey of 1009 people. The results of the survey indicated that x= 13.1 books and s= 16.2 books. A 99% confidence interval for this survey is (11.78, 14.42). Were people reading more in 1972 than they are today? а г Click the icon to view the table of areas under the t-distribution. (a) The 99% confidence interval for 1972 is (.). (Use ascending order. Round to two decimal places as needed.) Interpret the confidence interval. Which of the following is correct? (b) Were people reading more in 1972 than they are today? O A. Yes, people were reading more in 1972 than they are reading today, because the confidence intervals do not cross and have no common outcomes. O B. No, people were reading less in 1972 than they are reading today because the confidence intervals do not cross and have no common outcomes. O C. People were reading approximately the same number of books in 1972 as they are today because the intervals cross and have some common outcomes.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A poll conducted in 1972 asked 1009 people, "During the past year, about how many books, either hardcover or paperback, did you read either all or part of the way through?" Results of the survey indicated that x= 18.9 books and s= 19.9 books. (a) Construct a 99% confidence interval for the mean number of books read either all or part of during the preceding year. Interpret the interval. (b) Compare these results to a recent survey of 1009 people. The results of the survey indicated that x= 13.1 books and s= 16.2 books. A 99% confidence interval for this survey is (11.78, 14.42). Were people reading more in 1972 than they are today? Click the icon to view the table of areas under the t-distribution, (a) The 99% confidence interval for 1972 is ( ). (Use ascending order. Round to two decimal places as needed.) Interpret the confidence interval. Which of the following is correct? (b) Were people reading more in 1972 than they are today? O A. Yes, people were reading more in 1972 than they are reading today, because the confidence intervals do not cross and have no common outcomes. O B. No, people were reading less in 1972 than they are reading today because the confidence intervals do not cross and have no common outcomes. O C. People were reading approximately the same number of books in 1972 as they are today because the intervals cross and have some common outcomes.
Transcribed Image Text:A poll conducted in 1972 asked 1009 people, "During the past year, about how many books, either hardcover or paperback, did you read either all or part of the way through?" Results of the survey indicated that x= 18.9 books and s= 19.9 books. (a) Construct a 99% confidence interval for the mean number of books read either all or part of during the preceding year. Interpret the interval. (b) Compare these results to a recent survey of 1009 people. The results of the survey indicated that x= 13.1 books and s= 16.2 books. A 99% confidence interval for this survey is (11.78, 14.42). Were people reading more in 1972 than they are today? Click the icon to view the table of areas under the t-distribution, (a) The 99% confidence interval for 1972 is ( ). (Use ascending order. Round to two decimal places as needed.) Interpret the confidence interval. Which of the following is correct? (b) Were people reading more in 1972 than they are today? O A. Yes, people were reading more in 1972 than they are reading today, because the confidence intervals do not cross and have no common outcomes. O B. No, people were reading less in 1972 than they are reading today because the confidence intervals do not cross and have no common outcomes. O C. People were reading approximately the same number of books in 1972 as they are today because the intervals cross and have some common outcomes.
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