A point particle with charge q = -200 nC and mass m = 3.0x10-6 g is released from rest at the midpoint of a parallel-plate capacitor. The capacitor has plate separation d = 3.0 mm. The negative electrode is at x = 0 and the positive electrode is at x = d. The voltage across the capcitor has been measured to be AVC = 2.5 V. In this problem, ignore the weight of the particle. Give all numerical answers to two significant figures. a) How long does it take the particle to strike the capacitor plate, in seconds? b) Through what potential difference has the particle moved, in V?

A parallel-plate capacitor with a 0.1-mm air gap has a capacitance of 12 µF. (a) When this capacitor is connected to a battery, the maximum magnitude of charge on either plate is 0.18 mC (millicoulomb). What are the magnitude of the electric field between the plates and the energy density (energy per unit volume) in this region? (b) (c) Now suppose this capacitor is disconnected from the battery, and a slab of titanium dioxide (with dielectric constant 100) is inserted between the plates. Indicate whether each of the following quantities increases or decreases after insertion of the dielectric, as well as the factor by which each quantity changes: (i) potential difference across the plates; (ii) capacitance of the capacitor; and (iii) total energy stored in the capacitor. (No calculations are required here.) Calculate the total energy stored in the capacitor with dielectric described in part (b).

Two parallel-plate capacitors, 5.2 uF each, are connected in series to a 11 V battery. One of the capacitors is then squeezed so that its plate separation is halved. Because of the squeezing, (a) how much additional charge is transferred to the capacitors by the battery and (b) what is the increase in the sum of the charges: the charge on the positive plate of one capacitor plus the charge on the positive plate of the other capacitor? Give your answers in Coulombs.

A parallel plate capacitor with a capacitance of 0.86 F with a has plate area A and are separated by a distance d. It is charged up to 11 V. The capacitor is now disconnected from the battery. If the area of the plates increases by a factor of 3 and the separation decreases by a factor of 10, find the new charge on the capacitor in Coulombs.

An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = C

A parallel plate capacitor is charged to a potential of 3000 V and then isolated. Find the magnitude of the charge on the positive plate if the plates area is 0.40 m2 and the distance between the plates is 0.020 m. Group of answer choices 68 µC 54 µC 27 µC 18 µC

A parallel-plate capacitor in air has a plate separation of 1.58 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 270 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. (a) Determine the charge on the plates before and after immersion. before pC pC after (b) Determine the capacitance and potential difference after immersion. Cf = F AV = V (c) Determine the change in energy of the capacitor. nJ Need Help? Read It

Regarding the Earth and a cloud layer 800 m above the Earth as the "plates" of a capacitor, calculate the capacitance. Assume the cloud layer has an area of 1 km2 and that the air between the cloud and the ground is pure and dry. nF   Assume charge builds up on the cloud and on the ground until a uniform electric field of 2.0 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt. What is the maximum charge the cloud can hold? C