A point moves on a circular path with its position from rest defined by s = t^3 + 5t, where s and t are measured in meters and seconds, respectively. The magnitude of the acceleration is 8.39 m/s^2 when t = 0.66s. What is the diameter of the path?

A point moves on a circular path with its position from rest defined by s = t^3 + 5t, where s and t are measured in meters and seconds, respectively. The magnitude of the acceleration is 8.39 m/s^2 when t = 0.66s. What is the diameter of the path?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 51P: A person going for a walk follows the path shown in Figure P1.51. The total trip consists of four...

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