Related questions
Question
A point charge moving in a magnetic field of 1.24 Tesla experiences a force of 0.615E-11 N. The velocity of the charge is perpendicular to the magnetic field. In this problem, we use the points of the compass and `into' and `out of' to indicate directions with respect to the page. If the magnetic field points west and the force points out of the page, then give all possible correct answers for the charge Q. (Give all correct statments in alphabetical order: ACD, BE, etc.) A) Q is positive, moving south B) Q is positive, moving north C) Q is negative, moving north D) Q is negative, moving east E) Q is negative, moving south
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps with 2 images
Knowledge Booster
Similar questions
- A current-carrying wire of length 0.5 meters is placed perpendicular to a magnetic field of 0.4 Tesla. If the current flowing through the wire is 3 Amperes, what is the magnitude and direction of the magnetic force acting on the wire?arrow_forwardPlease provide what formulas used and explain whyarrow_forwardA singly charged ion (an ion missing one electron) with a velocity of 7,642 m/s is injected perpendicular to a 0.277 T magnetic field, and the ion moves in a circle of 66.8 mm radius. What is the molar mass of the ion in grams? (Remember to use grams and Avogadro's number to get molar mass. State the answer as an integer with no unit.) Moving to another question will save this response. Question & of aarrow_forward
- = 6.80 A and the wire lies in the plane of the rectangular loop, which carries a current I, = 10.0 A. The dimensions in the figure are In the figure below, the current in the long, straight wire is I, 0.100 m, a = 0.150 m, and { C = 0.420 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. magnitude direction to the leftarrow_forwardAn electron is traveling with a constan velocity vo in the presence of a uniform electric mg field E-Ek, where E- e (Here, m denotes the mass of the electron and e denotes its charge. g denotes the acceleration due to gravity). Gravity acts in the -Z direction. At t=0, when the electron is at the origin, a uniform magnetic field BB+BJ is switched on. Here. B, and B, are fixed positive BB. The coordinates of the point where the electron intersects the X-Y plane constants and B for the first time after t=0 are given by: 2amy B Zamy BB e (A) (C) 2 e B 2AMY, B B (B) (D) 2amv, B.B. e B 2rum BB B Lamy B.B B 2am B Barrow_forwardWrite down an expression for the force experienced by an electron moving with a velocity, v, in a magnetic field B. By equating this expression to the force required to cause electrons to follow a circular path of radius, r, derive an expression for the ratio, (?⁄?) for an electron in terms of the magnetic field strength, the radius of the circular path and the accelerating potential, V.arrow_forward
arrow_back_ios
arrow_forward_ios