A plot of potential energy versus position is shown for a 0.245 kg particle that can move along an x-axis as it is acted upon by a conservative force. In the graph, UA = 8 J, Uc = 22 J and U₁ = 31 J (corresponding to x>8). The particle is observed at the point where the potential energy U forms a curved "hill" to have kinetic energy of 3.01 J (At this point Ug = 14 J). What is the difference in particle speed when it is located at x= 6.5m compared to x=3.5m? Assume mechanical energy is conserved. [Find the speed for x=6.5m and subtract the speed for x=3.5m]

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Chapter1: Units, Trigonometry. And Vectors
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A plot of potential energy versus position is shown for a 0.245 kg particle that can move along
an x-axis as it is acted upon by a conservative force. In the graph, UA = 8 J, Uc = 22 J and Up
31 J (corresponding to x>8). The particle is observed at the point where the potential energy U
forms a curved "hill" to have kinetic energy of 3.01 J (At this point Ug = 14 J). What the
difference in particle speed when it is located at x= 6.5m compared to x=3.5m? Assume
mechanical energy is conserved. [Find the speed for x=6.5m and subtract the speed for
x=3.5m]
Δυ =
m/s
What is the range of possible particle motion? [Find the turnaround location for the left and right
side. The particle turns around when v=0. Take the difference in these (right value minus left
value) to get the range of the particle's motion]
Ax|
U (J)
UD
Uc
UA
0
1
2
3
4
x (m)
5
6
7
8
9
Transcribed Image Text:= A plot of potential energy versus position is shown for a 0.245 kg particle that can move along an x-axis as it is acted upon by a conservative force. In the graph, UA = 8 J, Uc = 22 J and Up 31 J (corresponding to x>8). The particle is observed at the point where the potential energy U forms a curved "hill" to have kinetic energy of 3.01 J (At this point Ug = 14 J). What the difference in particle speed when it is located at x= 6.5m compared to x=3.5m? Assume mechanical energy is conserved. [Find the speed for x=6.5m and subtract the speed for x=3.5m] Δυ = m/s What is the range of possible particle motion? [Find the turnaround location for the left and right side. The particle turns around when v=0. Take the difference in these (right value minus left value) to get the range of the particle's motion] Ax| U (J) UD Uc UA 0 1 2 3 4 x (m) 5 6 7 8 9
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