College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An outdoor, rectangular pool on campus is 4.5 meters [m] in width and 7.5 meters [m] in length. You may assume the depth of the pool is constant. If the pool is filled with pure water, the total pressure probe at the bottom of the pool reads 16.5 pound-force per square inch [psi]. What is the volume of the water in the pool in units of kiloliters [kL]? Length Force Mass Pressure 1 ft=12 in 1 N=0.225 lbf 1 kg=2.205 lbm 1 atm=101325 Pa 1 in=2.54 cm 1 slug = 14.5939 kg 1 atm=14.7 psi 1 m=3.28 ft Density of water=1000 kg/m3 Surface pressure=1 atmarrow_forwardA student enters in a Physics lab wants to know the atmospheric pressure, how he can measure it? Through certain device he founds that its value is 1.083 bar, if some amount of oxygen gas is introduced in the space above the Mercury level, due to which this level falls by 5 cm. Predict the volume of oxygen gas introduced above the Mercury level, if it is assumed that its height in a tube is 1 m with 2 cm2 area of cross section.arrow_forwardThe bottom of a rectangular swimming pool is 15 m × 25 m. If the atmospheric pressure above the swimming pool changes from 738 to 768 mm of mercury, determine the amount by which the force on the bottom of the pool increases? (Assume the density of mercury is 13.6 ✕ 103 kg/m3.)arrow_forward
- A 2.5-m-tall steel cylinder has a cross-sectional area of 1.5 m2. At the bottom, with a height of 0.5 m, is liquid water, on top of which is a 1-m high layer of gasoline, relative density of 0.8. The gasoline surface is exposed to atmospheric air at 101 kPa. What is the total mass of the liquid in the cylinder? 2000 kg O 1250 kg O 3250 kg O 1625 kgarrow_forwardA scientist is calculating the density of an ore sample. The scien- tist measures that the ore sample weighs 22.4 N in air. When the sample is suspended by a thin light cord and totally immersed in water, the tension in the cord is 14.2 N. What is the density of the ore sample that the scientist calculates. You can assume that any buoyant force from air is negligible.arrow_forwardWhat fraction of ice is submerged when it floats in freshwater, given the density of water at 0°C is very close to 1000 kg/m3 ?arrow_forward
- (Figure 1) shows a container with a cross section area of 15 cm² in which a layer of water floats on top of a layer of mercury. A 1.0 kg wood block with a cross-section area of 10 cm² floats on the water. The water depth, measured from the bottom of the block, is 25 cm. A pressure gauge at the bottom of the container reads 20 kPa. Figure 1.0 kg 25 cm h 10 cm² 15 cm² 1 of 1 > Part A = What is the depth dm of the mercury? Use pw = 1000 kg/m³ as the density of water and pm density of mercury. Express your answer in centimeters. ► View Available Hint(s) dm = Submit ——| ΑΣΦ Provide Feedback Request Answer ? cm Review 13,600 kg/m³ as the Next >arrow_forward2 6. A spherically shaped balloon has a radius of 12.5 m, and is filled with helium. How much extra mass can a cargo lift, assuming that the skin and the cargo of the balloon have a mass of 1050 kg? Neglect the buoyant force on the cargo volume itself. (The density of air is 1.29 kg/m³ and the density of helium is 0.179 kg/m³) ← NO 2 W S X H command #3 E D kg C с $ 4 ZEE!!! R F V G Search or type URL % R 10 5 T G A 6 MacBook Pro B Y H & 7 N U J * 00 8 M - ✪ K ( - O 9 dh V- V O L ) O command 1332 jil332 P > t : ; option { [ ? 4 1 + 11 FF Aarrow_forwardWhich of the following is true for the situation below? po is the atmospheric pressure, p is the density of the mercury. Pgas - Mercury 16 cm 6 ст Pgas = PO Pgas + Pg(0.06m) = PO Pgas = Po + pg(0.10m) Pgas = Po + pg(0.16m) O Pgas + Pg(0.10m) = Po %3D pgas + pg(0.16m) = Po Pgas = Po + pg(0.06m)arrow_forward
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