A pin-connected truss composed of members AB and BC is subjected to a vertical force P = 40 kN at joint B (see figure). Each member is of constant cross-sectional area: AAB = 0.004 m2 and 2 ABC = 0.002 m2. The diameter d of all pins is 20 mm, clevis thickness t is 10 mm, and the thickness t1 of the bracket is 15 mm. Determine the normal stress acting in each member and the shearing and bearing stresses at joint C.

The cross-sectional area of each member of the truss is 1.6 in2. Calculate the average normal stresses in members CE. D. 6 ft B F 8 ft 8 ft E 8 ft 6 ft 30 kips 6.833ksi O 6.250ksi O 10.417ksi O 9.362ksi

The truss ABC is constructed of three titanium (E Ti ​ =17.4×10 3 ksi) members. A horizontal force of 1.8 kip and an unknown force P are applied to the truss at point B as shown. Member AB has a cross-sectional area of 0.1in 2 , member BC has a cross-sectional area of 0.0025ft 2 , and member AC has a cross-sectional area of 0.2 in2.   b) Determine the magnitude of the force P that is required to displace the roller at point C to the right by .03 inches.

A pin-jointed truss ABC shown below consists of two links AB and BC. These links are 6 mm thick and 20 mm wide as shown. There are support brackets at A and C. All pins are 12 mm in diameter and a vertical force, P = 9 kN is applied at pin B as shown. The angle 0 =38 deg. and the angle ẞ = 0 + 20 deg. The normal stress in link AB is (The result is accurate to one decimal place, in the unit MPa. Please write down only the value of your final result) · 12mm 9 20mm -1.0m⋅ B