A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon? ОО OO 0.25 nm 150 nm 50 nm 2.0 nm not enough information given

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### Photon Wavelength Question

A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon?

- [ ] 0.25 nm
- [ ] 150 nm
- [ ] 50 nm
- [ ] 2.0 nm
- [ ] Not enough information given

**Explanation:**
To solve this problem, one should understand that the de Broglie wavelength can be computed using the relationship between a particle's momentum and its wavelength. For a photon, the wavelength (\(\lambda\)) is related to momentum (\(p\)) via the equation \( \lambda = \frac{h}{p} \), where \(h\) is Planck's constant.

For electrons, the de Broglie wavelength also follows \( \lambda = \frac{h}{p} \). Given that the photon and the electron have the same momentum in this problem, we can directly compare their wavelengths.

No diagrams or graphs are included with this question.
Transcribed Image Text:### Photon Wavelength Question A photon has a wavelength of 50 nm. What is the de Broglie wavelength of an electron that has the same momentum as this photon? - [ ] 0.25 nm - [ ] 150 nm - [ ] 50 nm - [ ] 2.0 nm - [ ] Not enough information given **Explanation:** To solve this problem, one should understand that the de Broglie wavelength can be computed using the relationship between a particle's momentum and its wavelength. For a photon, the wavelength (\(\lambda\)) is related to momentum (\(p\)) via the equation \( \lambda = \frac{h}{p} \), where \(h\) is Planck's constant. For electrons, the de Broglie wavelength also follows \( \lambda = \frac{h}{p} \). Given that the photon and the electron have the same momentum in this problem, we can directly compare their wavelengths. No diagrams or graphs are included with this question.
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