A person with a near point of 75.0 cmcm, but excellent distant vision, normally wears corrective glasses. But he loses them while traveling. Fortunately, he has his old pair as a spare. QA:  If the lenses of the old pair have a power of +2.25 dioptersdiopters , what is his near point (measured from his eye) when he is wearing the old glasses if they rest 2.00 cmcm in front of his eye?

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Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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A person with a near point of 75.0 cmcm, but excellent distant vision, normally wears corrective glasses. But he loses them while traveling. Fortunately, he has his old pair as a spare.

QA:  If the lenses of the old pair have a power of +2.25 dioptersdiopters , what is his near point (measured from his eye) when he is wearing the old glasses if they rest 2.00 cmcm in front of his eye?

 

QB: What would his near point be if his old glasses were contact lenses instead?

 

I got the answers

a) 29.63 cm

b) 27.63 cm

however they came out wrong. 

### Understanding Corrective Lenses

**Scenario:**
A person with a near point of 75.0 cm, but excellent distant vision, usually wears corrective glasses. He loses his new pair while traveling but has an old pair as a spare.

---

### Problem Statement: Part A

If the old pair of glasses has a lens power of +2.25 diopters, determine the person's new near point when wearing these glasses positioned 2.00 cm in front of his eyes.

#### Answer Calculation:

1. **Lens Power**: +2.25 diopters
2. **Distance from Eye**: 2.00 cm 
3. **Input Field for Answer**: 
   - \( d_{\text{near}} = 29.63 \, \text{cm} \)

- **Submit Button**: For answer submission.
- **Feedback**: The provided answer was incorrect. A prompt indicates "Try Again" with 2 attempts left.

### Key Concepts:

- **Diopter**: A unit of measurement for the optical power of a lens.
- **Near Point**: The closest point at which the eye can focus on an object clearly.

Understanding and applying these concepts can help solve similar vision correction problems efficiently.
Transcribed Image Text:### Understanding Corrective Lenses **Scenario:** A person with a near point of 75.0 cm, but excellent distant vision, usually wears corrective glasses. He loses his new pair while traveling but has an old pair as a spare. --- ### Problem Statement: Part A If the old pair of glasses has a lens power of +2.25 diopters, determine the person's new near point when wearing these glasses positioned 2.00 cm in front of his eyes. #### Answer Calculation: 1. **Lens Power**: +2.25 diopters 2. **Distance from Eye**: 2.00 cm 3. **Input Field for Answer**: - \( d_{\text{near}} = 29.63 \, \text{cm} \) - **Submit Button**: For answer submission. - **Feedback**: The provided answer was incorrect. A prompt indicates "Try Again" with 2 attempts left. ### Key Concepts: - **Diopter**: A unit of measurement for the optical power of a lens. - **Near Point**: The closest point at which the eye can focus on an object clearly. Understanding and applying these concepts can help solve similar vision correction problems efficiently.
**Part B**

**Question:**  
What would his near point be if his old glasses were contact lenses instead?  
Express your answer with the appropriate units.

**Input Field:**  
\( d_{\text{near}} = \)  
Value: 27.63  
Unit: cm

**Buttons and Options:**  
- Submit  
- Previous Answers  
- Request Answer

**Feedback:**  
Incorrect; Try Again; 2 attempts remaining

---

**Explanation:**  
The question asks for the calculation of the near point when using contact lenses. The answer inputted is 27.63 cm, but it was marked incorrect. Users have 2 more attempts to find the correct answer.
Transcribed Image Text:**Part B** **Question:** What would his near point be if his old glasses were contact lenses instead? Express your answer with the appropriate units. **Input Field:** \( d_{\text{near}} = \) Value: 27.63 Unit: cm **Buttons and Options:** - Submit - Previous Answers - Request Answer **Feedback:** Incorrect; Try Again; 2 attempts remaining --- **Explanation:** The question asks for the calculation of the near point when using contact lenses. The answer inputted is 27.63 cm, but it was marked incorrect. Users have 2 more attempts to find the correct answer.
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