A person with 100kg mass is standing erect on the tip of both feet. Find the contact force Cexerted by the bones -tibia and fibula- on the ankle joint, and the muscle force Fon the tendon of calcaneus at 37° with the horizontal. In this posture, the distance between the application points of C and F in a longitudinal cut is 5 cm; the distance between the application points of the Cand the normal force is 6 cm. F 37 5 ст 6 cm ... 10

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Chapter1: Units, Trigonometry. And Vectors
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A person with 100kg mass is standing erect on the tip of both feet. Find the contact force Cexerted by the
bones -tibia and fibula- on the ankle joint, and the muscle force Fon the tendon of calcaneus at 37° with
the horizontal. In this posture, the distance between the application points of Cand F in a longitudinal cut
is 5 cm; the distance between the application points of the Cand the normal force is 6 cm.
F
37
5 cm
6 cm
Transcribed Image Text:A person with 100kg mass is standing erect on the tip of both feet. Find the contact force Cexerted by the bones -tibia and fibula- on the ankle joint, and the muscle force Fon the tendon of calcaneus at 37° with the horizontal. In this posture, the distance between the application points of Cand F in a longitudinal cut is 5 cm; the distance between the application points of the Cand the normal force is 6 cm. F 37 5 cm 6 cm
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