A person who weighs 790 N Supports himselt on the ball of one foot The the foot on one side of the ankle joint, while the Achilles tendon pulls up on the foot on the other side of the joint. The center of gravity of the person is located right above the tibia Gastrocnemius- solcus muscles Tibia FAchilles Fribia Achilles tendon- Calcaneus (heel bone) 12.8 cm- 4.60 cm What is the magnitude of the downward force exerted on the ankle joint by the tibia? 2988 N.

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Chapter1: Units, Trigonometry. And Vectors
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A person who weighs 790 N supports himself on the ball of one foot. The normal force N= 790 N pushes up on the ball of
the foot on one side of the ankle joint, while the Achilles tendon pulls up on the foot on the other side of the joint. The
center of gravity of the person is located right above the tibia
Gastrocnemius-
soleus muscles
Tibia
Achilles
Fribia
Achilles tendon-
Calcancus
(heel bone)
12.8 cm
4.60 cm
What is the magnitude of the downward force exerted on the ankle joint by the tibia?
2988
Transcribed Image Text:A person who weighs 790 N supports himself on the ball of one foot. The normal force N= 790 N pushes up on the ball of the foot on one side of the ankle joint, while the Achilles tendon pulls up on the foot on the other side of the joint. The center of gravity of the person is located right above the tibia Gastrocnemius- soleus muscles Tibia Achilles Fribia Achilles tendon- Calcancus (heel bone) 12.8 cm 4.60 cm What is the magnitude of the downward force exerted on the ankle joint by the tibia? 2988
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