A person throws a ball with speed 102 m/s at a 45° angle. How many seconds faster would the ball arrive if the person threw the ball at the same speed and the same distance but made the trip in two identical bumps. Assume that there is no loss of speed at the bounce. Hint: Use R = v2/g * sin(2θ) and t=2*vy(sinθ)/g
A person throws a ball with speed 102 m/s at a 45° angle. How many seconds faster would the ball arrive if the person threw the ball at the same speed and the same distance but made the trip in two identical bumps. Assume that there is no loss of speed at the bounce. Hint: Use R = v2/g * sin(2θ) and t=2*vy(sinθ)/g
Related questions
Question
A person throws a ball with speed 102 m/s at a 45° angle. How many seconds faster would the ball arrive if the person threw the ball at the same speed and the same distance but made the trip in two identical bumps. Assume that there is no loss of speed at the bounce. Hint: Use R = v2/g * sin(2θ) and t=2*vy(sinθ)/g.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 4 steps