A pendulum is raised to a certain height and released from point A, as shown in the image below. At its release, the pendulum is also given an initial velocity of 14 m/s. Assuming that the effects of friction and air resistance can be ignored, what will be the maximum height that the pendulum can reach - that is , what is the height at point B? (Recall that g = 9.8 m/s2.)

Q: A car with mass m = 0.30 kg is attached to two springs, as shown in the figure below. The springs…

A:

Q: A toy gun uses a spring to project a 5.0-g soft rubber sphere horizontally. The spring constant is…

A: Given data : Projectile's mass, Spring constant, Barrel's length, Frictional force constant,…

Q: A car traveling 3.5 m/s coasts up a hill decreasing its speed to 2.2 m/s. Neglecting losses from…

A: From the conservation of energy:

Q: A block of mass m = 0.45 kg compressed against a spring of force constant 100 %3D

A: Given: Mass of block m=0.45kg Force constant k=100N/m Compression x=0.3m Distance d=1.5m.…

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A: (a) Let L denotes the string’s length, m denotes the bob’s mass, and vL denotes the speed of the bob…

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Q: A wooden block with mass 1.85 kg is placed against a compressed spring at the bottom of a slope…

A: Part A. The distance between point A and B is d=7.55 m. So, according to the given conditions, the…

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A:

Q: A 710 g block is dropped from a altitude h above a physics spring of spring constant 400 N/m. The…

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Q: An engineer is designing a spring to be placed at the bottom of an elevator shaft. If the elevator…

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A: This problem can be solved using the formula for the average of a function.

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A: Given data as per question velocity of swing =4.90 m/s  Child’s height above the ground = 0.810 m

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A: Step 1: Step 2: Step 3: Step 4:

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A: Given: x=15cm =0.15mm=675g=0.675kgk=225N/mμ=0.18l=20cm=0.2mh1=1.7mh2=1m

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Q: No friction D (H)

A: the spring constant K=1865N/m The block will stop at a distance D=2.4m the initial velocity with…

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A: Given data The height from which the simple pendulum is released is calculated as hr = 33.1 cm. The…

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A: m = 0.220 kg K = 120 N/m x1 = 11.2 cm = 0.112 m

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A:

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A: Length of string is Initial velocity is Find:Angle that the string makes with it's initial vertical…

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A: The equation of the acceleration is given by,

Q: What equation is used to calculate the speed, v, up the plane?

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A: Given data:  Mass of marble (m) = 17.0 g = 0.017 kg Compression in spring (x) = 16.0 cm = 0.16 m…

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Q: Let's say we have a spring with a constant of K= 300 N/m and this spring is attached to the incline…

A: Spring constant (k) = 300 Nm θ = 44od = 1.3 m m = 1 kg

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.