A particular fruit's weights are normally distributed, with a mean of 382 grams and a standard deviation of 16 grams. If you pick one fruit at random, what is the probability that it will weigh between 382 grams and 414 grams Round to 3 decimal places.

Q: A particular fruit's weights are normally distributed, with a mean of 356 grams and a standard…

A: From the given information, let X be the fruit’s weight. Mean fruit weights  Standard deviation…

Q: A particular fruit's weights are normally distributed, with a mean of 347 grams and a standard…

A: From the provided information, Mean (µ) = 347 Standard deviation (σ) = 25 X~N (347, 25)

Q: A particular fruit's weights are normally distributed, with a mean of 483 grams and a standard…

A: Given, Mean, μ = 483 standard deviation, σ=17  We have , Z = x-μσ

Q: A particular fruit's weights are normally distributed, with a mean of 648 grams and a standard…

A: Given distribution is normally distributed Let, X: Fruit's weights Mean, μ=648 Standard deviation,…

Q: A particular fruit's weights are normally distributed, with a mean of 706 grams and a standard…

A: Solution: Let X be the weight of a particular fruit. From the given information, X follows normal…

Q: A particular fruit's weights are normally distributed, with a mean of 768 grams and a standard…

A: Given, let X be the weight of fruits. The mean weight of the fruit’s is  The standard deviation of…

Q: A particular fruit's weights are normally distributed, with a mean of 799 grams and a standard…

A: It is given that the fruit weights follow normal distribution with mean 799 grams and standard…

Q: A particular fruit's weights are normally distributed, with a mean of 513 grams and a standard…

A: The population mean is 513. The population standard deviation is 18. The sample size is 22. We have…

Q: A manufacturer knows that their items have a normally distributed lifespan, with a mean of 10.5…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 264 grams and a standard…

A: Let X denotes the weight of a particular fruit. Therefore, X follows normal distribution with mean…

Q: A particular fruit's weights are normally distributed, with a mean of 783 grams and a standard…

A: It is given that the mean is 783 and the standard deviation is 24.

Q: A particular fruit's weights are normally distributed, with a mean of 681 grams and a standard…

A: Obtain the probability that it will weigh between 710 grams and 721 grams. The probability that it…

Q: A particular fruit's weights are normally distributed, with a mean of 445 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 517 grams and a standard…

A: Given:             Mean = µ = 517       Standard Deviation = σ = 32

Q: A particular fruit's weights are normally distributed, with a mean of 285 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 633 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 571 grams and a standard…

A: The random variable is fruit’s weight. It follows standard normal distribution. The population mean…

Q: A particular fruit's weights are normally distributed, with a mean of 582 grams and a standard…

A: Obtain the standard z-score for the random variable X equals 548. The standard z-score for the…

Q: A particular fruit's weights are normally distributed, with a mean of 798 grams and a standard…

A: According to the provided information, The mean is 798 grams  The standard deviation is 32

Q: A particular fruit's weights are normally distributed, with a mean of 636 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 557 grams and a standard…

A: From the given information, let X be the fruit’s weights. Here, X follows normally distribution with…

Q: A particular fruit's weights are normally distributed, with a mean of 327 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 583 grams and a standard…

A: Mean = 583 Standard deviation = 35 Sample size = 18

Q: A particular fruit's weights are normally distributed, with a mean of 463 grams and a standard…

A: We have given that,  A normal distribution with mean= 463 and standard deviation = 38. Here, From…

Q: A particular fruit's weights are normally distributed, with a mean of 794 grams and a standard…

A: given data normal distributionμ = 794 gramsσ = 38 grams

Q: particular fruit's weights are normally distributed, with a mean of 466 grams and a standard…

A: P(443<X<528)=?

Q: A particular fruit's weights are normally distributed, with a mean of 477 grams and a standard…

A: Mean u = 477grams Standard deviation o = 14 grams P(477 < x < 491) = ?

Q: particular fruit's weights are normally distributed, with a mean of 675 grams and a standard…

A: Given: Mean =675 Standard Deviation = 40 Find out The probability that it will weigh between 694…

Q: particular fruit's weights are normally distributed, with a mean of 282 grams and a standard…

A: We have given that.   X~N( μ , ?^2 )   μ=282   , ?=24   Z-score =( x - μ )/?

Q: A particular fruit's weights are normally distributed, with a mean of 600 grams and a standard…

A: Solution: Let X be the fruit’s weight. From the given information, X follows normal distribution…

Q: A particular fruit's weights are normally distributed, with a mean of 236 grams and a standard…

A: Mean = 236 Standard deviation = 31 Sample size = 14

Q: A particular fruit's weights are normally distributed, with a mean of 598 grams and a standard…

A: Given, mean μ=598 standard daviation is σ=19 Now we have to determine if we pick 22 fruits at…

Q: The average number of pounds of red meat a person consumes each year is 196 with a standard…

A: We are given,μ = 196σ = 22n = 60

Q: A particular fruit's weights are normally distributed, with a mean of 736 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 432 grams and a standard…

A: A particular fruit's weights are normally distributed, with a mean of 432 grams and a standard…

Q: A particular fruit's weights are normally distributed, with a mean of 419 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 560 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 575 grams and a standard…

A: R command has utilized to find the probability.

Q: A particular fruit's weights are normally distributed, with a mean of 376 grams and a standard…

A: given data normal distributionμ = 376σ = 38P(315<x<357) = ?

Q: A particular fruit's weights are normally distributed, with a mean of 370 grams and a standard…

A: The normal probability distribution is widely used to find the probability for the continuous random…

Q: A particular fruit's weights are normally distributed, with a mean of 448 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed with a mean of 288 grams and a standard…

A: Solution

Q: A particular fruit's weights are normally distributed, with a mean of 771 grams and a standard…

A:

Q: A particular fruit's weights are normally distributed, with a mean of 3/1 grams and a standard…

A: given data normal distribution μ=371σ=11P(386<x<397)=?

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.