A particular coin is biased. Each time it is flipped, the probability of a head is P (H) = 0.95 and the probability of a tail is P(T) = 0.05. Each flip is independent of the other flips. The coin is flipped twice. Let X be the total number of times the coin shows a head out of two flips. So the possible values of X are x = 0, 1, or 2. a) How would we find P(X= 2) ? (Pick all right answers) Type in Rstudio: choose(1, 1)* 0.95^0 * 0.05^2 Type in Rstudio: choose(2, 2)* 0.95^2 * 0.05^0 □ P(X = 2) = (²) P(H)² (1 – P(H))²—2 □ P(X = 2) = (₁) P(H)¹ (1 – P(H))2–1 Knowing that P(X = 1) = 0.095 and P(X= 2) = 0.9025 P(X = 0) = 0.0025 (Enter the exact value) b) What is the probability that X≥ 1? 0.0025 (Enter the exact value) c) Compute the expected value of X. μχ = d) Compute the variance X. of = (Enter the exact value) (Enter the exact value) compute the following probabilities:

this is incorrect and due at 5:00 please help

Hello Please help me make the correct decimal placement for 0.9854 if it is necessary to round to three decimal places as​ needed. Thank you for your time.  Gene

Only need help with 1 & 2. Must be calculated in Excel. Thanks