A particle's position is 7 = (ct? – 2dt³)î + (2ct² – dt³)¡, where c and d are positive constants. Is there any time t > 0 when the particle is (a) at rest or (b) accelerating in the x-direction only? If either answer is "yes," find the time(s).
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- The position of a particle in space at time tis: r(t) = (sec(t)) * i + (tan t) * j + 4/3 tk. Write the particle's velocity at time t = (pi / 6) as the product of its speed and direction.٤٣ B/s ۱۰:۰۹ ص .in the direction of the force TO FO choose the correct answer The acceleration Vector in cartizan Cordinat writin by the formulla Ⓒazé x + j X+kŹ =¿Ÿ+K Ⓒă= cx+jŸ+k² @a=ix + ³y +kż a b с do time derivative of velocity is called acceleration rate velocity docs.google.com/forms/d/ तंA particle moves through 3-space in such a way that its acceleration is a(t)= 8sin 2ri +8cos 2tj+e'k . where t is time measured in seconds. The initial velocity of the particle is v, = 2i – 3j+k. At time t = t , find i) the velocity vector of the particle. ii) the scalar tangential and normal components of acceleration.
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