A particle with mass 0.5 kg is moving in x-y plane. Its velocity is described as a function of time v(t) = (3î – 4tj), t 2 0. The unit of t is second and the unit of velocity is meter per second. Find (a) the initial velocity of the particle. (b) the magnitude of the acceleration of the particle at = 5s. (e) the displacement of the particle at = 5s.

At time t = 13 s, the velocity of a particle moving in the x-y plane is v=0.05i + 2.54j m/s. By time t = 13.05 s, its velocity has become -0.12i+2.42j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav= e= i i m/s² O

The velocity of a particle moving in the xy plane is given by = ( 5.50 r- 5.00 P)i + 9.00). with V in meters per second and t- 0l in seconds. At t-1.40 s and in unit-vector notation, what are lal the xcomponent and (bi the y component of the acceleration? ) When of ever) is the acceleration zero? (d) At what positive time does the speed eoual 100 ms? 1 unit (al Number } unit This anwer hannunts degrees Number O Number Unit (d) Number Unit Hint Pa GO Tutorial Save for Later times Attempts: unlimited Smit Arr

A sports car moves at a constant velocity and travels 120m in 5.0s. If it brakes and comes to a stop in 4.0s, what is the magnitude of acceleration (assumed constant) in m/s2 and in g's (g=9.80 m/s2)