A particle of mass 3.94 x 10^-27 kg has a potential energy of 7.19 * 10^-15 J, independently of its position. If its energy is 11.0 \times 10^-15 J, what is its angular wave number?

A 2.5 cm object is placed 30 cm in front of a converging lens. Behind the lens, 80 cm away, is a concave mirror with a focal length of 15 cm. Sketch the ray diagram and determine the final location and height of the object.

A small particle has charge -4.30 μC and mass 2.00×10-4 kg. It moves from point A, where the electric potential is VA = 260 V, to point B, where the electric potential VB = 960 V is greater than the potential at point A. The electric force is the only force acting on the particle. The particle has a speed of 4.60 m/s at point A. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Electric force and electric potential. - Part A What is its speed at point B? Express your answer in meters per second. ΜΕ ΑΣΦ v = Submit Request Answer Part B Is it moving faster or slower at B than at A? Faster Slower Submit Request Answer ? m/s

Find the average binding energy per nucleon of 2 Mo and 82 Kr. (For the atomic masses, see this table. Enter your answers to at least two decimal places.) 42 36 (a) 92 Mo 42 MeV/nucleon 82 (b) Kr 36 MeV/nucleon