A particle of mass 2.5kg moves according to the equation x(t)=10t?, where x is in meters and t is in seconds. The force (in N) acts on the particle is Select one: a. 25 b. 40 с. 35 d. 50

A girl weighing 45kg is standing on the floor, exerting a downward force of 200N on the floor. The force exerted on her by the floor is

A particle of mass 5.30 kg is acted on by a single force of 32.2 N. If the particle starts at rest, how far does it travel in the first 15.0 s?

4. A 3 kg mass slides down an inclined plane that has an angle of 25 degrees. It starts at rest and travels a distance of 16 meters. What is its final velocity if Hk=0.15?

DETAILS PREVIOUS ANSWERS SERPSE10 7.4.P.016. MY NOTES ASK YOUR TEACHER The force acting on a particle is F, = (10x – 17) N, where x is in meters. (a) Make a plot of this force versus x from x = 0 to x = 3.00 m. F (N) F (N) 50 20 40 10 3어 20 0,5 1.0 15 20 2,5 x (m) 30 10 -10 x (m) 3.0 0.5 1.0 1.5 2.0 2.5 F (N) F (N) 0,5 1.0 + x (m) 2,5 30 1아 1.5 2,0 -1어 2,5 x (m) 30 -20 0,5 1,0 15 -30 -10 - 40 -20 - 50 (b) From your graph, find the net work done by this force on the particle as x = 0 to x = 2.55 m. (Include the correct sign.) it moves from Need Help? Read It

Solve the following problem and follow the instructions.    Final Answer -> (5.2.50) 4.57 m/s2, 15.7 N

If a 3.73 kg object is placed on a frictionless incline of 67.3 ° and released from rest, what is speed of the object down the incline after traveling a distance of 1.18 m? Enter a number rounded to 2 decimal places and assume it has proper Sl units.

If you have a ball with a mass of 6.00kg, that has an initial velocity of vA=(2.00i + 5.00j)m/s and a final velocity of vB=(-2.00i + 8.00j)m/s, What is the change in velocity in unit vector format?   a. -4.00i + 3.00j   b. -2.83i + 3.61j   c. 4.00i – 3.00j   d. 0.00i + 13.0j

A 1.5 kg rocket is shot from the ground with an initial velocity of 50 m/s. How high does go before stopping?

(Assume no friction forces) A train of 100 railroad cars each with a mass of 6 x 104 kg is being pulled by a locomotive that has a mass of 4.5 x 105 kg.  The train leaves the freight yard at 12:00 noon on May the 5th.  It starts from an initial velocity of 0.  It takes the locomotive 8 kilometers to get the train up to a speed of 75 km/hr.  The train then travels at an average speed of 75 km/hr for 4,200 km.  After 4,200 km the train decelerates to a stop in 20 minutes.  How long in minutes (to the nearest hundredth of a minute) did it take to reach 75 km/hr at the beginning?  How much work was done to get the train to 75 km/hr.  What was the KE of the train when it reached 75 km/hr?  How much work was done on the train during the time it traveled the 4,200 km at 75 km/hr?  What is the total distance the train traveled from beginning to end to the nearest km?  What date and time does it arrive at its destination? (Date: Hour: min)? What is the work required to stop the train? What was…