A particle moves with position function s=14-4t³8t² + 25t, t20 (a) At what time does the particle have a velocity of 25 m/s? (Enter your answers as a comma-separated list.) t = S (b) At what time is the acceleration 0? (Round your answer to two decimal places.) t = S What is the significance of this? At this time, the acceleration changes from negative to positive and the velocity attains its minimum value. At this time, the acceleration changes from positive to negative and the velocity attains its minimum value. At this time, the acceleration changes from negative to positive and the velocity attains its maximum value. At this time, the acceleration changes from positive to negative and the velocity attains a value of zero. At this time, the acceleration changes from positive to negative and the velocity attains its maximum value.

Suppose you walk 16 m straight west and then 23 m straight north as shown inthe figure. How far are you from your starting point in meters? What is the angle of displacement measured west of north in degrees?

Please solve and answer correctly please 1.56 m/s was incorrect

A jet is flying at a constant velocity. The jet's velocity vector has an east component of 215 and a north m S m component of 1811 Overall, how fast is the jet flying in? A Moving to another question will save this S S response. Question 1 3 A Moving to another question will save this response. Ć a pois A jet is flying at a constant velocity. The jet's velocity vector has an east component of 215 m/s and a north componerft of 181 m/s. Overall, how fast is the jet flying in m/s? I Question 1