A particle moves along a horizontal line. Its position on the line in t seconds is given by s(t) = -t(t²- 24t+ 180). Here, a zero position represents the origin, a negative position is to the left of the origin, and a positive position is to the right of the origin. If v(t) and a(t) are the velocity and acceleration, respectively, of the particle at t seconds, then their signs are given in the table below: t v(t) a(t) (0,6) 6 0 + + (6,8) 8 (8,10) 10 (10, +00) + + 0 + + 0 - - 1. Where is the particle located when it attains its absolute maximum velocity?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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A particle moves along a horizontal line. Its position on the line in t seconds is given by
s(t) = -t(t²- 24t+180).
Here, a zero position represents the origin, a negative position is to the left of the origin, and a positive position
is to the right of the origin. If v(t) and a(t) are the velocity and acceleration, respectively, of the particle at
t seconds, then their signs are given in the table below:
(0,6) 6
0
t
v(t)
a(t)
1. Where is the particle located when it attains its absolute maximum velocity?
-
+
(6,8) 8 (8, 10) 10 (10, +00)
+
0
+ 0
+
+ +
-
Transcribed Image Text:A particle moves along a horizontal line. Its position on the line in t seconds is given by s(t) = -t(t²- 24t+180). Here, a zero position represents the origin, a negative position is to the left of the origin, and a positive position is to the right of the origin. If v(t) and a(t) are the velocity and acceleration, respectively, of the particle at t seconds, then their signs are given in the table below: (0,6) 6 0 t v(t) a(t) 1. Where is the particle located when it attains its absolute maximum velocity? - + (6,8) 8 (8, 10) 10 (10, +00) + 0 + 0 + + + -
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