A particle is subjected to the action of two forces:F1 = 2.5 i-3j+ 6 k [kN] and F2 = 5 i+6j-5k [kN]. The magnitude of the resultantforce is:%3D%3DSelect one:Oa. FR=-8.139 [kN]%3DOb. FR 8.139 [kN]Oc. FR = 5 [kN]Od. FR=-5 [kN]Activate Winype here to seatch445 PE

We know to determine the resultant of two forces in 3d, we need to add then vectorically, then to…

A particle is subjected to the action of two forces: F1 = 2.5 i-3 j+6 k [kN] and F2 = 5i+6j-5k [kN]. The magnitude of the resultant %3D force is: Select one: a. FR = - 8.139 [kN] O b. FR = 8.139 [kN] O c. FR = 5 [kN] Od. FR = - 5 [kN]

A particle is subjected to the action of two forces: F1 = 2.5 i-3 j+6 k [kN] and F2 = 5i+6j-5k [kN]. The magnitude of the resultant %3D force is: Select one: a. FR = - 8.139 [kN] O b. FR = 8.139 [kN] O c. FR = 5 [kN] Od. FR = - 5 [kN]

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

A particle is subjected to the action of two forces:
F1 = 2.5 i-3j+ 6 k [kN] and F2 = 5 i+6j-5k [kN]. The magnitude of the resultant
force is:
%3D
%3D
Select one:
Oa. FR=-8.139 [kN]
%3D
Ob. FR 8.139 [kN]
Oc. FR = 5 [kN]
Od. FR=-5 [kN]
Activate Win
ype here to seatch
445 PE

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