A particle is aimed at a mark, which is in the horizontal plane through the point of projection, falls a meters short of it when the elevation is a and goes beyond it b meters too far when the elevation is 3. Show that if the velocity of projection in each case be the same, then the proper elevation, 0, is a sin 28 +b sin 2a a +b 1 0 = =s Question 2: (a) A projectile started from O at an elevation a. After t seconds its position appeared to have an elevation 3 as seen from O. Prove that the initial velocity was gt cos B 2sin (a – B) (b) A stone is projected with velocity v and elevation 0 from a point O on level ground so as to hit a mark P on a wall whose distance from O is a the height of P above the ground being b. Prove that 20 (a sin 0 cos 0 – b cos² 0) = ga² Also prove that the requisite velocity of projection is least when 0 = +;, where a is the elevation of P as seen from O.
A particle is aimed at a mark, which is in the horizontal plane through the point of projection, falls a meters short of it when the elevation is a and goes beyond it b meters too far when the elevation is 3. Show that if the velocity of projection in each case be the same, then the proper elevation, 0, is a sin 28 +b sin 2a a +b 1 0 = =s Question 2: (a) A projectile started from O at an elevation a. After t seconds its position appeared to have an elevation 3 as seen from O. Prove that the initial velocity was gt cos B 2sin (a – B) (b) A stone is projected with velocity v and elevation 0 from a point O on level ground so as to hit a mark P on a wall whose distance from O is a the height of P above the ground being b. Prove that 20 (a sin 0 cos 0 – b cos² 0) = ga² Also prove that the requisite velocity of projection is least when 0 = +;, where a is the elevation of P as seen from O.
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 1 images