College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A parallel plate capacitor of capacitance C0 has plates of area A with separation d between them. When it is connected to a battery of voltage V0, it has charge of magnitude Q0 on its plates. The plates are pulled apart to a separation 2d while the capacitor remains connected to the battery. After the plates are 2d apart, the magnitude of the charge on the plates and the potential difference between them are
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- A parallel-plate capacitor under the key of a keyboard has circular plates that are separated by 0.0500 mm and filled with a dielectric with k = 4.00. When the potential difference across the plates is 5.00 V , the magnitude of the charge on each plate is 8.897 pC. What is the radius of one of the plates? When the key is pressed, the distance between the plates decreases, increasing the capacitance to 1.85 pF. What is the separation between the plates when the key is pressed?arrow_forwardThe plates of a parallel-plate capacitor have a separation of 3.52 mmmm , and each has an area of 15.0 cm2cm2 . Each plate carries a charge of magnitude 3.85×10−8 CC . The plates are in vacuum. a) what is the capacitance? b)What is the potential difference between the plates? c)What is the magnitude of the electric field between the plates?arrow_forwardA parallel plate capacitor has capacitance C0 = 15.0 pF when there is air between the plates. The separation between the plates is 1.00 mm. A dielectic with K=3.50 is inserted between the plates of the capacitor, completely feeling the volume between the plates. The capacitor is connected with a battery. Find the magnitude of charge on each plate if the electric field between the plates is 3.00 x 104 V/m.arrow_forward
- A certain parallel-plate capacitor consists of two plates, each with area 2.00 x 102cm2, and separated by a gap of 0.400 cm. (Assume air as the dielectric material.) a) What is the capacitance of this capacitor? b) If the capacitor is connected across a 500.0 V source, what charge will it hold? c) What is the magnitude of the electric field between the plates of the capacitor? (under the conditions of part b)?arrow_forwardConsider a parallel-plate capacitor made up of two conducting plates with dimensions 34 mm × 18 mm. a) If the separation between the plates is 1.1 mm, what is the capacitance, in pF, between them? b) If there is 0.32 nC of charged stored on the positive plate, what is the potential, in volts, across the capacitor? c) What is the magnitude of the electric field, in newtons per coulomb, inside this capacitor? d) If the separation between the plates doubles, what will the electric field be if the charge is kept constant?arrow_forwardA parallel plate capacitor is charged up so that the upper plate carries a charge of 0.2C. In a vacuum, the potential difference between the plates is 2V. When a certain dielectric material is placed between the plates, the potential difference drops to 1.5V. Calculate the dielectric constant of the material.arrow_forward
- A parallel plate capacitor has a potential difference between its plates of 1.6 V and a plate separation distance of 2.5 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.4 is inserted between the plates? O 290 V/m O 110 V/m O 170 V/m O 240 V/m O 190 V/marrow_forwardRegarding the Earth and a cloud layer 800 m above the Earth as the "plates" of a capacitor, calculate the capacitance. Assume the cloud layer has an area of 1 km2 and that the air between the cloud and the ground is pure and dry. nF Assume charge builds up on the cloud and on the ground until a uniform electric field of 2.0 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt. What is the maximum charge the cloud can hold? Carrow_forward
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