A parallel-plate capacitor is made of two square plates 30 cm on a side and 1 mm apart. The capacitor is connected to a 90-V battery. Hint a. What is the energy stored in the capacitor? Energy stored in the capacitor is 3.2E-6 X µJ. b. With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is 1.075275E-5 X µJ. c. This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is HJ.

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The plates of an air  filled parallel-plate capacitor with a plate area of 16.0 Cm and a separation of 9.00 Mm are charged to a 145-v potential difference. After the plates are disconnected from the source. A porcelain dielectric with k=18 Is inserted between the plates of the capacitor. a. What Is the charge on the capacitor before and After the dielectric is inserted? b. what Is the capacitance of the capacitor After the dielectric Is inserted? c. What Is the potential difference between the plates of the capacitor After the dielectric is inserted? What Is the magnitude of the change in the energy stored in the capacitor After the dielectric is inserted?

A capacitor of 3.23µF has an area of 6.35mm^2. Determine the separation distance between the two plates. If the new capacitance is now 5.63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8.99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown? Prove your answer. Follow this format- Given: Required: Equtions: Solution: Answer:

A 12.6 μF circular parallel-plate capacitor is connected to an 11.3 V battery. Part A: What is the load on each plate? Part B:What would be the load on the plates if the distance between the plates was doubled while the shawl was connected to the battery? Part C :If the radii of the plates were doubled and the capacitor was connected to the same battery, what would be the loads on the plates?

A 3.50 cm in diameter parallel plate capacitor has a 1.50 mm spacing. The electric field inside the capacitor is 3 x 105 V/m.a. What is the potential different across the capacitor?b. How much charge is on each plate?c. If the charge on the plates remains the same as the plates are pulled apart will the voltage difference Increase decrease or stay the same?

A 30 mF capacitor is charged to 60 V and then connected across an initially uncharged 60 mF capacitor. What is the final potential difference across the 60 mF capacitor? A. OV B. 60 V C. 40 V D. 180 V E. 20 V

A fully charged capacitor can store 500 J of energy. Assuming it is charged using the typical 120V of potential, what must be the capacitance? a. 23 mF b. 69 mF c. 128 mF d. 424 mF

Each plate of the capacitor has a cross sectional area of 0.45m2. A 5mm-thick dielectric having a permittivity of 4 is inserted between the plates. This capacitor is then placed across a 100 V source. Determine the ff:a. Capacitance of the capacitorb. The charge on the capacitorc. The magnitude of the electric field between the platesd. electric potential energy stored in a charged capacitor