A parallel plate capacitor is connected to a DC power supply with potential difference V= 20 V. A dielectric slab of thickness d = 10 cm is then inserted between the plates of the capacitor, completely filling the space between them. The dielectric constant of the slab is K = 2. Calculate the induced surface charge density, a, on the surface of the slab (permittivity of vacuum is Eg= 8.85x10-12F/m). A. 1,77 nC/m? • B. 7.12 nC/m2 • C. 3.56 nC/m2 O D. 0.89 nC/m2
A parallel plate capacitor is connected to a DC power supply with potential difference V= 20 V. A dielectric slab of thickness d = 10 cm is then inserted between the plates of the capacitor, completely filling the space between them. The dielectric constant of the slab is K = 2. Calculate the induced surface charge density, a, on the surface of the slab (permittivity of vacuum is Eg= 8.85x10-12F/m). A. 1,77 nC/m? • B. 7.12 nC/m2 • C. 3.56 nC/m2 O D. 0.89 nC/m2
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Transcribed Image Text:A parallel plate capacitor is connected to a DC power supply with potential difference V= 20 V. A dielectric slab of thickness d = 10 cm is then inserted between the plates of the capacitor, completely filling the space between
them. The dielectric constant of the slab is K = 2. Calculate the induced surface charge density, o, on the surface of the slab (permittivity of vacuum is en= 8.85x1o-12F/m).
A. 1.77 nC/m?
B. 7.12 nC/m2
C. 3.56 nC/m2
D. 0.89 nC/m2
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