A parallel-plate capacitor initially has Quartz between its plates and carries charge ±Q. A different dielectric is then inserted between the plates without changing the charge. If the energy stored in the capacitor decreases to 72% of its initial value, what is the value of x for the new dielectric? K =

An engineer builds a parallel-plate capacitor with adjustable spacing between the plates. When the plates are at their initial separation, the capacitance is 2.00 uF. (a) At this capacitance, the capacitor is connected to a 20.00 V battery. After fully charging, how much energy (in ) is stored in the capacitor? μJ (b) The battery is then disconnected. Without discharging the capacitor, the engineer then doubles the separation between the plates. At this point, how much energy (in µ3) is stored in the capacitor? p] (c) Without changing this new separation between the plates, the capacitor is discharged, and then reconnected to the 20.00 V battery. Now, after fully charging, how much energy (in p) is stored in the capacitor? p3

A capacitor has a charge of 2.0 µC when connected to a 5.5 V battery. How much energy is stored in this capacitor (in µJ)? +

When a 360-nF air capacitor is connected to a power supply, the energy stored in the capacitor is 15.6 μJ. While the capacitor is connected to the power supply, a slab of dielectric is inserted that completely fills the space between the plates. This increases the stored energy by 23.8 μJ. What is the dielectric constant of the slab?

A parallel-plate capacitor has square plates that have a length equal to 1 cm separated by 1.2 mm. It is connected to a battery and charged to 11 V. How much energy is stored in the capacitor? Use -12 F/m. &o=8.85×10 Energy stored in a capacitor, E: ✓ J

Four parallel-plate capacitors all carry the same amount of charge on their plate. As can be seen in the figure, capacitors A and C have their plates separated by distance d, while B and D have twice the separation (2d). Capacitors C and D contain dielectrics with a dielectric constant of 5. Which option ranks the capacitors of increasing capacitance? dielectric (K = 5) D vacuum B - 2d- -d- -2d- А, С, В, D ОА, В, С, D В, А, D, C D, C, В, A D, B, C, A

Two parallel plates having equal and opposite charges with area L x L separation d is filled with a dielectric material as shown in the Figure. The related dielectric constant varies with zask=a+ Here, a 46 cm, b -92 cm, d 0.31 cm and L=1m are given. Find the capacitance of this capacitor in 10-11 Farad. Take o=10-¹¹ C²/Nm². Answer:

A certain substance has a dielectric constant of 2.2 and a dielectric strength of 22 MV/m. If it is used as the dielectric material in a parallel-plate capacitor, what minimum area should the plates of the capacitor have to obtain a capacitance of 10 × 10²µ F and to ensure that the capacitor will be able to withstand a potential difference of 3.4 kV? Number i Units

A parallel plate capacitor with plate separation of 4.25 cm has plates whose area has dimensions of length 3.18 cm and width 2.32 cm. Calculate the capacitance of this capacitor (in picofarads) if a dielectric material with a dielectric constant of 3.24 is placed between the plates. pF

A capacitor is designed as shown in Figure a. Calculate the magnitude of capacitance using the value A = 1 cm2 , d = 2 mm, κ1 = 4.9, κ2 = 5.6, and κ3 = 2.1 b. Calculate stored energy