A Parallel plate capacitor has plate each of length 20.0 cm and breadth 10.0 cm. The separation between the plates is 1 mm. Calculate: (i) The potential difference between the plate if charge of 1 mc is given to capacitor. (ii) with the same charge of 1 me, if the separation between plates is doubled, what is the new potential differences?

+Q HF (a) Determine the electric potential difference, AV, across a capacitor with plates of area, A, separation, d, and charge, +Q and -Q. (b) Calculate the electric field in between the two plates. (c) Assuming the negative plate is at zero electric potential, calculate the electric potential, V at the midpoint between the plates.

Question 17 ( The effective area of each plate of a parallel plate capacitor is 2.1 m2. The capacitor is filled with neoprene rubber (k = 6.4). When a 6.0-V potential difference exists across the plates of the capacitor, the capacitor stores 4.0 µC of charge. a) What is the capacitance of the capacitor? (-. b) Determine the plate separation of the capacitor.(

Capacitance  Problem 8:  A 0.072 μF capacitor is being held at a potential difference of 466 μV.    Part (b)  If you measure the size of each plate to be 49 cm2, how far apart are the plates, in micrometers?