A parallel-plate capacitor has a plate area of 0.4 m2,  a plate separation of 0.67 mm and a dielectric with a value of κ = 3.0. If the charge on each plate has a magnitude of 4.1x 10–6 C, deposited while a battery was connected, then the potential difference across the plates is approximately: Write your numerical answer to one decimal place, show your units with your written work

What total energy is stored in the capacitors in the figure below (C, = 0.343 µF, C, = 36.7 µF) if 1.80 x 104 J is stored in the 2.50 µF capacitor? (Enter your answer to at least three significant figures.) 1.861 What is the potential difference across the entire combination? What is the potential difference across the 2.50 uF capacitor compared to the potential difference across the combination? What is the potential difference across the series combination compared to the potential difference across the 2.50 µF capacitor? J 2.50 µF

A parallel plate capacitor has a capacitance of 6.3 µF when filled with a dielectric. The area of each plate is 1.4 m2 and the separation between the plates is 1.06  10-5 m. What is the dielectric constant of the dielectric?

Find the total capacitance and the total charge if the voltage supply is 143 volts. Please provide a detailed solution and I have attached the formulas that we use.

Please type the final answer instead of writing thanks

Figure shows a parallel plate capacitor of plate area A and plate separation d. The gap between plates is filled with materials of dielectric constants K1 = 2, K2 = 1, K3 = 3 and K4 = separations shown on the figure. 6 with area and A a) Find the capacitance in terms of C if C = co4. b) For A = 8cm? and d = 8mm and potential difference V = 100 V applied the plates, find d/2 %3D d ↑d/4 K1 charge on the capacitor plates. K4 K1 d/2 c) Find energy stored between the plates. d/2 A/4 A/4 K2 t/p A/2 A/2

A constant electric field É = (3 N/C)j is present in space. Find the work done by the electric field in Joules, if a positive charge q = 2 Cmoves from Tin = 2î + 3î +k to řin = 5î – 2î – 2k. where r is in meters. (Put a minus sign on the left for negative work; Ex: -1. Do not put a plus sign for a positive value.) Answer:

What is the capacitance of a capacitor that stores 1.3 μC of charge on its plates when a voltage of 3.3 V is applied between them?

A parallel plate capacitor with plate area 1.5 m2, and plate separation 0.002 cm, and filled with neoprene rubber, has 9 V applied between the plates. What is the charge value Q for this setup? Please enter your value in units of micro Coulombs. This means, for example, if your answer is 9 x 10-6 C, you need to enter 9 into the box below.

What total energy is stored in the capacitors in the figure below (C, = 0.623 µF, C, = 22.7 µF) if 1.80 x 104 J is stored in the 2.50 µF capacitor? (Enter your answer to at least three significant %3D figures.) 2.50 µF