a) Numerically, what is the image distance, di in meters?  b) Is this real or virtual?  c) Numerically, what is the image height, hi?

= 1.0). An object (A) is Assume that a thin lens (r, placed in the left side of lens (d = 45mm) and the image of the object is located in the right side of the lens at position (B) (d' = 90mm). 1) Compute the refraction index of the lens (n2); = -r2 = 40mm) is placed in the air (n 2) If placing another negative thin lens (f2 = -180mm) immediately behind the first lens to create a doublet lens in which the spacing between two lenses is zero (as shown in the right figure), what is the focal length of this doublet? 3) Where is the final image position (C) of the object (A) through this new doublet? (Note: Assuming this doublet lens is a combined thin lens too without considering its thickness).

an object of height 5 cm is placed 20 cm in front of a converging lens at focal length 10 cm. Behind the converging lens, and 25cm from it, there is a diverging lens of the focal length of 6 cm. Find the location of the final image, in centimeters, with respect to teh diverging lens. what is the magnification of the final image? what is the height of the final image?

HW Q7

A) how far from the object should this lens be placed? B) what focal length eyepiece would give an overall magnification of -55? C) what focal length eyepiece would give an overall magnification of -100?

Your friend has glasses. When you look stralght at their eyes when they are wearing glasses, you notice that their eyes appear right-side up and 1.1 times larger in height (and width) compared to when they are not wearing glasses. Assume that their glasses are 2.0 cm away from their eyes. What is the focal length of their glasses? Hint: What Is the object and where is the image?

Please help me solve the following.