A normal vector for the plane through the points (2, 5, 1), (3, 7, 0), and (2, 5, 2) is <

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A: Given: So,               ∫lnx34xdx=14·∫lnx3xdxLet u=ln x=14·∫ u3du=14·u44Substitute back u=lnx=14·l...

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