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A nonuniform horizontal bar of mass m is supported by two massless wires against gravity. The left wire makes an angle a with the horizontal, and the right wire makes an angle B. The bar has length L. (Figure 1) Part A What is the position of the center of mass of the bar, measured as distance x from the bar's left end? Express your answer in terms of a, B, and L. • View Available Hint(s) να ΑΣφ ? Submit Figure <) 1 of 1 Provide Feedback

A nonuniform horizontal bar of mass m is supported by two massless wires against gravity. The left wire makes an angle a with the horizontal, and the right wire makes an angle B. The bar has length L. (Figure 1) Part A What is the position of the center of mass of the bar, measured as distance x from the bar's left end? Express your answer in terms of a, B, and L. • View Available Hint(s) να ΑΣφ ? Submit Figure <) 1 of 1 Provide Feedback

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Problem Statement A nonuniform horizontal bar of mass \( m \) is supported by two massless wires against gravity. The left wire makes an angle \( \alpha \) with the horizontal, and the right wire makes an angle \( \beta \). The bar has length \( L \). #### Question: What is the position of the center of mass of the bar, measured as distance \( x \) from the bar's left end? Express your answer in terms of \( \alpha \), \( \beta \), and \( L \). #### Solution: Input the value of \( x \) in the provided textbox (calculator interface available). ### Diagram Explanation: The figure depicts a horizontal bar supported by two wires. The left wire forms an angle \( \alpha \) with the horizontal, and the right wire forms an angle \( \beta \). The length of the bar is labeled \( L \), and the position \( x \) is measured from the bar’s left end. - **Coordinate System:** The diagram includes an \( xy \)-coordinate system with the positive direction indicated in a counter-clockwise manner. - **Position \( x \):** This is the distance from the left end of the bar to its center of mass. This setup is used to solve for the center of mass based on the given angles and length.
Transcribed Image Text:### Problem Statement A nonuniform horizontal bar of mass \( m \) is supported by two massless wires against gravity. The left wire makes an angle \( \alpha \) with the horizontal, and the right wire makes an angle \( \beta \). The bar has length \( L \). #### Question: What is the position of the center of mass of the bar, measured as distance \( x \) from the bar's left end? Express your answer in terms of \( \alpha \), \( \beta \), and \( L \). #### Solution: Input the value of \( x \) in the provided textbox (calculator interface available). ### Diagram Explanation: The figure depicts a horizontal bar supported by two wires. The left wire forms an angle \( \alpha \) with the horizontal, and the right wire forms an angle \( \beta \). The length of the bar is labeled \( L \), and the position \( x \) is measured from the bar’s left end. - **Coordinate System:** The diagram includes an \( xy \)-coordinate system with the positive direction indicated in a counter-clockwise manner. - **Position \( x \):** This is the distance from the left end of the bar to its center of mass. This setup is used to solve for the center of mass based on the given angles and length.
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