A noninverting amplifier is being designed to have a closed-loop gain of 36 dB. What op-amp gain is required to have the gain error less than 0.15 percent?

Given: 

$A_v^{Ideal} = 36 dB$

$A_v^{Ideal} = 36 dB$

To convert the value from decibel to gain is shown as:

$A_v^{Ideal} ={10}^{\frac{GainindB}{20} }$

Substitute the value of gain value in the following equation is shown as:

$$\begin{gathered} A_v^{Ideal} ={10}^{\frac{36}{20} } \\ {A}_v^{Ideal} =63.1 \end{gathered}$$

The fractional gain error can be written as:

$FGE\le \frac{1}{1+T}$ 

Substitute the value of FGE=0.15% in the following equation is shown as:

$$\begin{gathered} 0.15\%\le \frac{1}{1+T} \\ \frac{0.15}{100}\le \frac{1}{1+T} \end{gathered}$$

Here,

$T\ge 666$